The Reactance of a Capacitor is t<u>he resistance it has when alternating current (A/C) with a specific frequency (f) passes through it. </u>This is measured in ohms (Ω) and its formula is:
(1)
Where:
is the Reactance in ohms (Ω)
is the frequency of the alternating current in Hertz (
)
is the Capacitance of the Capacitor in Farad (
)
In this case we have a 25 mF capacitor with an applied frequency of 400 Hz.
Note 
Well, with the given data we have to solve (1):
Then:
XC=0.0159 Ω This is the Reactance of the Capacitor
Answer:
A
Step-by-step explanation:
The end behaviour as x gets larger and positive ( right- hand end )or larger and negative ( left- hand end )is determined by the term of the greatest degree.
For p(x) that is 4
, with
• Even degree (8) and positive leading coefficient (4), then
as x → ∞ , p(x) → ∞ and
as x → - ∞ , p(x) → ∞
372.733 i tjink thats the asnwer
It’s 45%
Explanation = 31900-22000/22000 • 100 = 45%
The answer is of the figure is 24
