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sukhopar [10]
3 years ago
9

It has been estimated that the population of Indianapolis is growing at a rate of 0.9% per year. Assuming that the population gr

owth continues at this rate and the population of Indianapolis was 1,988,817 in January of 2016, estimate the expected population of Indianapolis in January of 2019. (Please help me with this question. I’m genuinely stuck.)
Mathematics
1 answer:
sweet [91]3 years ago
8 0

Hi there!

Ok, so, here are the important facts:

Yearly population growing rate : 0.9%

Population in January 2016 : 1 988 817

Population in January 2019 (3 years later) : x


First off, you need to calculate 0.9% of the population in January 2016 to figure out the number of people it represents :

Saying 0.9% of 1 988 817 is like saying 0.9% times 1 988 817!


\frac{0.9}{100} = \frac{?}{1 988 817}


To solve this, you can use the cross product method :

(1 988 817 × 0.9) ÷ 100 = ?

1 789 935.3 ÷ 100 = ?

17 899.353 = ?


So 0.9% represents a growing rate of 17 899.353 people (we'll keep the decimals just to be more precise in the end).


Now, since you want to know the expected population in January 2019, 3 years later, you need to multiply 17 899.353 by 3 and then add the result to the population number in 2016 :


(17 899.353 × 3) + 1 988 817 = x

53 698.059 + 1 988 817 = x

2 042 515.059 = x

2 042 515 ≅ x (Since we are talking about a population, which represents a certain amout of people, you need to round the number)


Your answer is : The expected population of Indianapolis in January 2019 would be of 2,042,515 people.


There you go! I really hope this helped, if there's anything just let me know! :)

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The area of the equilateral, isosceles and right angled triangle are 12.6mm², 9.61in² and 16.81yds² respectively.

<h3>What is the area of the equilateral, isosceles and right angle triangle?</h3>

Note that:

The area of an Equilateral triangle is expressed as A = ((√3)/4)a²

Where a is the dimension of the side.

The area of an Isosceles triangle is expressed as A = (ah)/2

Where a is the dimension of the base and h is the height.

The area of a Right angled triangle is expressed as A = (ab)/2

Where a and b is the dimension of the two sides other than the hypotenuse.

For the Equilateral triangle.

Given that;

  • a = 5.4mm
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A = ((√3)/4)(5.4mm)²

A = ((√3)/4)( 29.16mm² )

A = 12.6mm²

Area of the Equilateral triangle is 12.6mm²

For the Isosceles triangle.

Given that;

  • Base a = 3.4in
  • Slant height b = 5.9in
  • height h = ?
  • Area A = ?

The height h is the imaginary line drawn upward from the center of a.

First, we calculate the height using Pythagorean theorem

x² = y² + z²

Where x = b = 5.9in, y = a/2 = 3.4in/2 = 1.7in, and z = h

(5.9in)² = (1.7in)² + h²

34.81in² = 2.89in² + h²

h² = 34.81in² - 2.89in²

h² = 31.92in²

h = √31.92in²

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A = (3.4in × 5.65in )/2

A = 19.21in²/2

A = 9.61in²

Area of the Isosceles triangle is 9.61in².

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A = (ab)/2

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A = 16.81yds²

Area of the Right angled triangle is 16.81yds²

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Learn more about Pythagorean theorem here: brainly.com/question/343682

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