Answer:
![n_1=-\frac{1}{3}+1.31i\\n_2=-\frac{1}{3}-1.31i](https://tex.z-dn.net/?f=n_1%3D-%5Cfrac%7B1%7D%7B3%7D%2B1.31i%5C%5Cn_2%3D-%5Cfrac%7B1%7D%7B3%7D-1.31i)
Step-by-step explanation:
To solve this problem you must apply the proccedure shown below:
1. You have that the quadratic formula is:
![n=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B-b%2B%2F-%5Csqrt%7Bb%5E%7B2%7D-4ac%7D%7D%7B2a%7D)
2. To solve the quadratic equation you must substitute the values, you have that:
![a=6\\b=4\\c=11](https://tex.z-dn.net/?f=a%3D6%5C%5Cb%3D4%5C%5Cc%3D11)
Then:
![n=\frac{-4+/-\sqrt{4^{2}-4(6)(11)}}{2(6)}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B-4%2B%2F-%5Csqrt%7B4%5E%7B2%7D-4%286%29%2811%29%7D%7D%7B2%286%29%7D)
3, Therefore, you obtain the following result:
![n_1=-\frac{1}{3}+1.31i\\n_2=-\frac{1}{3}-1.31i](https://tex.z-dn.net/?f=n_1%3D-%5Cfrac%7B1%7D%7B3%7D%2B1.31i%5C%5Cn_2%3D-%5Cfrac%7B1%7D%7B3%7D-1.31i)
I don't know about millimeters but there are around 3785 milliliters in a gallon.
Answer:
B
Step-by-step explanation:
I just did it in illuminate