Answer:
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Step-by-step explanation:
f(x)=\frac{-8x^4+3x^2-7x}{4x^2-4}=\frac{-8x^2+3-7/x}{4-4/x^2}
As x approaches -\infty, f(x) will tend to -\infty
1. 9/20 = 0.45
2. 0.46
3. 0.48
The area of a rectangle is (length) times (width).
So you have to find a pair of numbers that multiply to produce 6 .
If you only stick to whole numbers, then I don't think there are three
different ones. You're going to need one pair that multiply to 6 and
are not both whole numbers.
After I explain how to solve problems, I hate to give answers. But with
all due respect, I have a feeling that I haven't nudged you enough yet
for you to use my explanation to find the answers on your own.
So here are some answers:
1 and 6
2 and 3
and sets of dimensions that are not both whole numbers, like
0.6 and 10
1.2 and 5
1.25 and 4.8
1.5 and 4
2.4 and 2.5
Q = -60 and P ≠ 32 will result in an equation with no solutions. (Both conditions must be met.)
_____
For Q = -60 and P = 32, there will be an infinite number of solutions. For any other values of Q and P, the solution is
.. x = (32 -P)/(Q +60)
