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Brut [27]
3 years ago
7

Geometry!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Stella [2.4K]3 years ago
8 0

<u>Given</u>:

Given that O is the center of the circle.

The radius of the circle is 3 m.

The measure of ∠AOB is 30°

We need to determine the length of the major arc ACB

<u>Measure of major ∠AOB:</u>

The measure of major angle AOB can be determined by subtracting 360° and 30°

Thus, we have;

Major \ \angle AOB=360-30

Major \ \angle AOB=330^{\circ}

Thus, the measure of major angle is 330°

<u>Length of the major arc ACB:</u>

The length of the major arc ACB can be determined using the formula,

<u></u>m \widehat{ACB}=(\frac{\theta}{360})2 \pi r<u></u>

Substituting r = 3 and \theta=330, we get;

m \widehat{ACB}=(\frac{330}{360})2 \pi (3)

m \widehat{ACB}=\frac{1980}{360}\pi

m \widehat{ACB}=5.5 \pi

Thus, the length of the major arc ACB is 5.5π m

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a car is traveling at a stead rate of speed. the points (1,40) and (3,y) appear on a graph of the cars distance over time. what
maria [59]

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Do you have a graph?

Step-by-step explanation:

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3 years ago
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3. What is the scale factor of Figure B to Figure A?
xxMikexx [17]

Answer:

2.5

Step-by-step explanation:

From the diagram, figure B was enlarged to obtain figure A.

The two figures are therefore similar.

The corresponding sides are in the same proportion. That constant value of the proportion is called scale factor.

It is given by:

k =  \frac{image \: length}{corresponding\:object \: length}

Figure B is the image of A

k =  \frac{10}{4}  =  \frac{25}{10}  = \frac{21.5}{8.6} =   2.5

Therefore the scale factor is 2.5

4 0
3 years ago
Part A: Abe rented a bike at $36 for 5 days. If he rents the same bike for 8 days, he has to pay a total rent of $48. Write an e
worty [1.4K]

a)

y=4 x +(1.6 X 10)


b)

y=4x +16


c)

x=0 y=0+16 (0,16)

x=1 y=4 +16 (1,20) first day it cost $20

x=2 y=8+16 (2,24) second day it cost $24

x=3 y=12+16 (3, 28) third day it cost $28


plot (0,16) , (1,20), (2,24), (3, 28)


i hope this help

7 0
3 years ago
jabu left town A to travel to town B at 6:00 a.m. he drove at an average speed of 80km/h. At 8.30a.m. Sipho left town A to trave
7nadin3 [17]

Answer:

Sipho catches up Jabu at 6:30 pm

Step-by-step explanation:

Jabu left town A to travel to town B at 6:00 a.m. he drove at an average speed of 80km/h.

At 8:30 am, when Sipho leaves, we will have traveled 2.5 hours at 80 km/h, so he will be 80*2.5 = 200 km ahead.

From then, his position will be given by:

J(t) = 200 + 80t

Sipho left town A to travel to town B. He drove at an average speed of 100 km/h.

His position will be given by:

S(t) = 100t

At what time will Sipho catch up jabu?​

He will catch up in t hours, and t is found when:

S(t) = J(t)

So

100t = 200 + 80t

20t = 200

t = \frac{200}{20} = 10

He will catch up 10 hours after 8:30 am, that is, 6:30 pm.

Sipho catches up Jabu at 6:30 pm

4 0
2 years ago
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