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Brut [27]
3 years ago
7

Geometry!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Stella [2.4K]3 years ago
8 0

<u>Given</u>:

Given that O is the center of the circle.

The radius of the circle is 3 m.

The measure of ∠AOB is 30°

We need to determine the length of the major arc ACB

<u>Measure of major ∠AOB:</u>

The measure of major angle AOB can be determined by subtracting 360° and 30°

Thus, we have;

Major \ \angle AOB=360-30

Major \ \angle AOB=330^{\circ}

Thus, the measure of major angle is 330°

<u>Length of the major arc ACB:</u>

The length of the major arc ACB can be determined using the formula,

<u></u>m \widehat{ACB}=(\frac{\theta}{360})2 \pi r<u></u>

Substituting r = 3 and \theta=330, we get;

m \widehat{ACB}=(\frac{330}{360})2 \pi (3)

m \widehat{ACB}=\frac{1980}{360}\pi

m \widehat{ACB}=5.5 \pi

Thus, the length of the major arc ACB is 5.5π m

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Jesse is saving the money he earns in his piggybank. He had already earned
spin [16.1K]

Answer:

Jesse will have $120.

Step-by-step explanation:

First you need to set up your equation. We know Jesse has $60 already and that he charges $15 per lawn. Your equation will look something like this:

15x+60=?

Then you plug in the 4 lawns he did:

15(4)+60=

Then you solve and get 120! :)

PS Parenthesis mean you are multiplying. Same thing as saying

15 x 4 + 60= 120

6 0
3 years ago
Caroline walked 3 miles to warm up. She then ran at a rate of 7 miles per hour. Find the total
Alex

Answer:

14 miles

added with the miles she warmed up is 17 miles

5 0
2 years ago
Read 2 more answers
Can someone help me and show me how to solve this?
DedPeter [7]
XYA = (104 -52)/2

52 /2 = 26

the answer is 26 degrees
8 0
2 years ago
Read 2 more answers
7.
mamaluj [8]

15/.14.3456... ** V125)
3 0
3 years ago
Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. The
Tems11 [23]

Answer:

The 84% confidence interval for the population proportion that claim to always buckle up is (0.74, 0.80).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

They randomly survey 387 drivers and find that 298 claim to always buckle up.

This means that n = 387, \pi = \frac{298}{387} = 0.77

84% confidence level

So \alpha = 0.16, z is the value of Z that has a p-value of 1 - \frac{0.16}{2} = 0.92, so Z = 1.405.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 - 1.405\sqrt{\frac{0.77*0.23}{387}} = 0.74

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 + 1.405\sqrt{\frac{0.77*0.23}{387}} = 0.8

The 84% confidence interval for the population proportion that claim to always buckle up is (0.74, 0.80).

6 0
2 years ago
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