Question

Nitrosyl bromide decomposes according to the following equation. 2NOBr (g) 2NO (g) Br2 (g) A sample of NOBr (0.64 mol) was placed in a 1.00-L flask containing no NO or Br2. At equilibrium the flask contained 0.46 mol of NOBr. How many moles of NO and Br2, respectively, are in the flask at equilibrium

Answer 1

Answer:

Moles of NO = 0.18

Moles of Br2 = 0.18

Explanation:

The given reaction with ICE table is:

           $2NOBr(g)\rightarrow 2NO(g)+Br_{2}(g)$

Initial          0.64                    -      -

Change      -2x                    +2x    +x

Equilb        (0.64-2x)               2x    2x

At equilibrium:

[NOBr] = 0.64-2x

NO = Br2 = 2x

The equilibrium moles of NOBr  = 0.46

$i.e.\ 0.64-2x = 0.46\\x = 0.09\ mols$

Moles of NO = Moles of Br2 = 2x = 2(0.09) = 0.18 moles