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Yuri [45]
3 years ago
7

What is the volume of 35.0 g of propylene glycol if the density of propylene glycol is 1.036 g/ cm3?

Chemistry
1 answer:
Len [333]3 years ago
3 0
Mass = 35.0 g

density = 1.036 g/cm³

volume = ?

therefore:

D = m / V

1.036 = 35.0 / V

V = 35.0 / 1.036

V = 33.784 cm³

answer D
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The most practical would be milliliters
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What amount (moles) is represented by each of these samples?
Zinaida [17]
<h3>Answer:</h3>

                  a)  Moles of Caffeine  =  1.0 × 10⁻⁴ mol

                  b) Moles of Ethanol   =  4.5 × 10⁻³ mol

<h3>Solution:</h3>

Data Given:

                  Mass of Caffeine  =  20 mg  =  0.02 g

                  M.Mass of Caffeine  =  194.19 g.mol⁻¹

                  Molecules of Ethanol  =  2.72 × 10²¹

Calculate Moles of Caffeine as,

                               Moles  =  Mass ÷ M.Mass

Putting values,

                               Moles  =  0.02 g ÷ 194.19 g.mol⁻¹

                                Moles  =  1.0 × 10⁻⁴ mol

Calculate Moles of Ethanol as,

                                                         As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.

The relation between Moles, Number of Particles and Avogadro's Number is given as,

                          Number of Moles  =  Number of Molecules ÷ 6.022 × 10²³

Putting values,

                          Number of Moles  =  2.72 × 10²¹ Molecules ÷ 6.022 × 10²³

                          Number of Moles  =  4.5 × 10⁻³ Moles

5 0
3 years ago
What quantity is measured in mol/dm³?
natima [27]
L
M =  \frac{n}{V}  \\ M = \frac{mol}{L}  \\ or \\ M =  \frac{mol}{ {dm}^{3} }
mol/dm³ is measure for molarity
3 0
3 years ago
What is the mass of 4.56 moles of copper (ii) fluoride​
musickatia [10]

Answer:

463.0 g.

Explanation:

  • We can use the following relation:

<em>n = mass/molar mass.</em>

where, n is the mass of copper(ii) fluoride​ (m = 4.56 mol),

mass of copper(ii) fluoride​ = ??? g.

molar mass of copper(ii) fluoride​ = 101.543 g/mol.

∴ mass of copper(ii) fluoride​ = (n)(molar mass) = (4.56 mol)(101.543 g/mol) = 463.0 g.

7 0
3 years ago
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