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Yuri [45]
3 years ago
7

What is the volume of 35.0 g of propylene glycol if the density of propylene glycol is 1.036 g/ cm3?

Chemistry
1 answer:
Len [333]3 years ago
3 0
Mass = 35.0 g

density = 1.036 g/cm³

volume = ?

therefore:

D = m / V

1.036 = 35.0 / V

V = 35.0 / 1.036

V = 33.784 cm³

answer D
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1 year ago
What element has 2 electrons in the 4s sub level?
ruslelena [56]

is the Calcium because the calcium in group two which group two has 2 electron and also calcium and Potassium 4s sub level group potassium has 1 electron. :)


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3 years ago
Given the following formula for calculating the ionization energy of one-electron species such as Li2+, He+, and H, calculate th
Yuki888 [10]

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The answer is "32819.9 \ \frac{J}{mol}\\\\"

Explanation:

Boron: 5^{B}\to 1s^2 2s^2 2p^1

\Delta E=-2.18\times 10^{-18}\ \frac{J}{atom}\ (\frac{1}{\infity^2}-\frac{1}{n^2_{initial}})(z^2) (6.022\times 10^{23}\ \frac{atom}{mol})\\\\

      =-2.18\times 10^{-18}\ \frac{J}{atom}\ (0-\frac{1}{1})(5^2) (6.022\times 10^{23}\ \frac{atom}{mol})\\\\ =2.18\times 10^{-18}\times 25 \times 6.022\times 10^{23}\ (\frac{J}{mol})\\\\ =328.199 \times 10^{5}\ (\frac{J}{mol})\\\\ =32819 \times 10^{3}\ (\frac{J}{mol})\\\\ =32819.9 \ (\frac{J}{mol})\\\\

4 0
3 years ago
Describe one way in which uranium is disposed of.
Romashka-Z-Leto [24]

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In the oxide form, uranium can be disposed of as low-level radioactive waste at an approved disposal facility. Approximately 350,000 tons of anhydrous HF are used annually in the United States.

Explanation:

7 0
3 years ago
2H2(g)+2NO(g)→2H2O(g)+N2(g) Part A If the concentration of NO changed from 0.100 M to 0.025 M in the first 15 minutes of the rea
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Answer:

0.0025 M/min

Explanation:

The rate of a reaction can be calculated for an element, based on its stoichiometric coefficient. For a reaction:

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Where Δ[X] is the variation of the concentration of the X compound, Δt is the time variation, and the signal of minus in the reagents compounds is because they are disappearing, so Δ[X] will be negative, and r must be positive. So, for the reaction given:

r = -(1/2)x(Δ[NO]/Δt)

r = -(1/2)x( (0.025 - 0.1)/15)

r = 0.0025 M/min

6 0
3 years ago
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