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daser333 [38]
2 years ago
12

With the help of balanced chemical equation explain what happens when:(1)Zinc is put in dilute hydrochloric acid (2)Zinc is put

in concentrated sodium hydroxide.(3)Hydrogen is passed over hot tungsten oxide.(40Hydrogen is reacted with carbon monoxide in presence of a catalyst.

Chemistry
2 answers:
Viktor [21]2 years ago
8 0

Answer:

1) Zn(s)+2HCl(aq)--->ZnCl_{2}+H_{2}(g)

2) Zn+2H_{2}O+2NaO-->Na_{2}Zn(OH)_{4}+H_{2}(g)

3) 3H_{2}(g)+W_{2}O_{3}--->3H_{2}O+2W(s)

4) CO(g)+2H_{2}(g)--->CH_{3}OH

Explanation:

The following happens:

(1)Zinc is put in dilute hydrochloric acid

There is an evolution of hydrogen gas as the Zinc undergoes oxidation by hydrogen and it reduces the hydrogen to hydrogen gas.

Zn(s)+2HCl(aq)--->ZnCl_{2}+H_{2}(g)

(2)Zinc is put in concentrated sodium hydroxide.

Again there is evolution of hydrogen gas and formation of zincate sodium. This happens when we heat the mixture.

Zn+2H_{2}O+2NaO-->Na_{2}Zn(OH)_{4}+H_{2}(g)

(3)Hydrogen is passed over hot tungsten oxide.

The hydrogen reduces the tungsten metal during the reaction and it gives solid tungsten metal.

3H_{2}(g)+W_{2}O_{3}--->3H_{2}O+2W(s)

(4) Hydrogen is reacted with carbon monoxide in presence of a catalyst.

This is producer gas reaction.

CO(g)+2H_{2}(g)--->CH_{3}OH

UkoKoshka [18]2 years ago
6 0
Find the attached document.

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The question is incomplete, here is the complete question:

Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

Atmospheric Gas         Mole Fraction      kH mol/(L*atm)

           N_2                         7.81\times 10^{-1}         6.70\times 10^{-4}

           O_2                         2.10\times 10^{-1}        1.30\times 10^{-3}

           Ar                          9.34\times 10^{-3}        1.40\times 10^{-3}

          CO_2                        3.33\times 10^{-4}        3.50\times 10^{-2}

          CH_4                       2.00\times 10^{-6}         1.40\times 10^{-3}

          H_2                          5.00\times 10^{-7}         7.80\times 10^{-4}

<u>Answer:</u> The solubility of hydrogen gas in water at given atmospheric pressure is 1.48\times 10^{-10}M

<u>Explanation:</u>

To calculate the partial pressure of hydrogen gas, we use the equation given by Raoult's law, which is:

p_{\text{hydrogen gas}}=p_T\times \chi_{\text{hydrogen gas}}

where,

p_A = partial pressure of hydrogen gas = ?

p_T = total pressure = 0.380 atm

\chi_A = mole fraction of hydrogen gas = 5.00\times 10^{-7}

Putting values in above equation, we get:

p_{\text{hydrogen gas}}=0.380\times 5.00\times 10^{-7}\\\\p_{\text{hydrogen gas}}=1.9\times 10^{-7}atm

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{H_2}=K_H\times p_{H_2}

where,

K_H = Henry's constant = 7.80\times 10^{-4}mol/L.atm

p_{H_2} = partial pressure of hydrogen gas = 1.9\times 10^{-7}atm

Putting values in above equation, we get:

C_{H_2}=7.80\times 10^{-4}mol/L.atm\times 1.9\times 10^{-7}atm\\\\C_{CO_2}=1.48\times 10^{-10}M

Hence, the solubility of hydrogen gas in water at given atmospheric pressure is 1.48\times 10^{-10}M

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