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daser333 [38]
3 years ago
12

With the help of balanced chemical equation explain what happens when:(1)Zinc is put in dilute hydrochloric acid (2)Zinc is put

in concentrated sodium hydroxide.(3)Hydrogen is passed over hot tungsten oxide.(40Hydrogen is reacted with carbon monoxide in presence of a catalyst.

Chemistry
2 answers:
Viktor [21]3 years ago
8 0

Answer:

1) Zn(s)+2HCl(aq)--->ZnCl_{2}+H_{2}(g)

2) Zn+2H_{2}O+2NaO-->Na_{2}Zn(OH)_{4}+H_{2}(g)

3) 3H_{2}(g)+W_{2}O_{3}--->3H_{2}O+2W(s)

4) CO(g)+2H_{2}(g)--->CH_{3}OH

Explanation:

The following happens:

(1)Zinc is put in dilute hydrochloric acid

There is an evolution of hydrogen gas as the Zinc undergoes oxidation by hydrogen and it reduces the hydrogen to hydrogen gas.

Zn(s)+2HCl(aq)--->ZnCl_{2}+H_{2}(g)

(2)Zinc is put in concentrated sodium hydroxide.

Again there is evolution of hydrogen gas and formation of zincate sodium. This happens when we heat the mixture.

Zn+2H_{2}O+2NaO-->Na_{2}Zn(OH)_{4}+H_{2}(g)

(3)Hydrogen is passed over hot tungsten oxide.

The hydrogen reduces the tungsten metal during the reaction and it gives solid tungsten metal.

3H_{2}(g)+W_{2}O_{3}--->3H_{2}O+2W(s)

(4) Hydrogen is reacted with carbon monoxide in presence of a catalyst.

This is producer gas reaction.

CO(g)+2H_{2}(g)--->CH_{3}OH

UkoKoshka [18]3 years ago
6 0
Find the attached document.

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Taking into account the reaction stoichiometry, 8 moles of Ag can be produced from 8 moles of AgNO₃ and 5 moles of Zn.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 AgNO₃ + Zn → 2 Ag + Zn(NO₃)₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • AgNO₃: 2 moles
  • Zn: 1 mole
  • Ag: 2 moles
  • Zn(NO₃)₂: 1 mole

<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of Zn reacts with 2 moles of AgNO₃, 5 moles of Zn reacts with how many moles of AgNO₃?

amount of moles of AgNO_{3}= \frac{5 moles of Znx2 moles of AgNO_{3}}{1 mole of Zn}

<u><em>amount of moles of AgNO₃= 10 moles </em></u>

But 10 moles of AgNO₃ are not available, 8 moles are available. Since you have less moles than you need to react with 5 moles of Zn, AgNO₃ will be the limiting reagent.

<h3>Moles of Ag formed</h3>

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 2 moles of AgNO₃ form 2 moles of Ag, 8 moles of AgNO₃ form how many moles of Ag?

amount of moles of Ag=\frac{8 moles of AgNO_{3}x2 moles of Ag }{2 moles of AgNO_{3}}

<u><em>amount of moles of Ag= 8 moles</em></u>

Then, 8 moles of Ag can be produced from 8 moles of AgNO₃ and 5 moles of Zn.

Learn more about the reaction stoichiometry:

<u>brainly.com/question/24741074</u>

<u>brainly.com/question/24653699</u>

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