Answer:
Explanation:
1 ) tire of radius 0.381 m rotating at 12.2 rpm
12.2 rpm = 12.2 /60 rps
n = .20333 rps
angular speed
= 2πn
= 2 x 3.14 x .20333
= 1.277 rad / s
2 ) a bowling ball of radius 12.4 cm rotating at 0.456 rad/s
angular speed = .456 rad/s
3 ) a top with a diameter of 5.09 cm spinning at 18.7∘ per second
18.7° per second = (18.7 / 180) x 3.14 rad/s
= .326 rad/s
4 )
a rock on a string being swung in a circle of radius 0.587 m with
a centripetal acceleration of 4.53 m/s2
centripetal acceleration = ω²R
ω is angular velocity and R is radius
4.53 = ω² x .587
ω = 2.78 rad / s
5 )a square, with sides 0.123 m long, rotating about its center with corners moving at a tangential speed of 0.287 m / s
The radius of the circle in which corner is moving
= .123 x √2
=.174 m
angular velocity = linear velocity / radius
.287 / .174
1.649 rad / s
The perfect order is
4 ) > 5> 1 >2>3.
It will act upon a buoyant force on the magnitude of which is equal to weight of the fluid
Base in your question that ask for the distance that the remote control would extend beyond the edge where as a remote control is 22cm long and has a mass of 0.08kg =, base on my calculation the answer would be 1.27cm i hope you understand my answer
Then, it would continue the motion in direction of resultant force...
Answer:
1.4 s
Explanation:
Given the following data;
Quantity of charge, Q = 2.5 C
Current = 1.8 A
To find the time required;
Mathematically, the quantity of charge passing through a conductor is given by the formula;
Quantity of charge, Q = current * time
Substituting into the formula, we have;
2.5 = 1.8 * time
Time = 2.5/1.8
Time = 1.4 s
