How do I solve this?

Mathematics

1 answer:

Crazy boy [7]3 years ago

7 0

Answer:

71°

142°

Step-by-step explanation:

$\because QS \: is \: the \: bisector \: of \: \angle \: PQR\\\therefore m\angle RQS =m\angle PQS\\\because m\angle RQS = 71\degree...(given) \\ \huge \red{ \boxed{\therefore m\angle PQS = 71\degree}} \\ \because \: m\angle \: PQR = m\angle PQS + m\angle RQS \\ \because \: m\angle \: PQR = 71\degree + 71\degree \\ \huge \purple{ \boxed{\therefore \: m\angle \: PQR = 142\degree}}$

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mafiozo [28]

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mutiply the bracket by 2

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6x+x+14= 70 ( combine like terms)

7x+14= 70

move 14 to the other side

sign changes from +14 to -14

7x+14-14=70-14

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divide both sides by 7

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3 years ago

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Step-by-step explanation:

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3 years ago

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Alexeev081 [22]

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3 years ago

A plane traveled 1248 miles to Ft. Worth and back. The trip there was with the wind. It took 12

Artemon [7]

speed of the plane in still air is 76 m/s and speed of the wind is 28 m/s .

Step-by-step explanation:

Here we have , A plane traveled 1248 miles to Ft. Worth and back. The trip there was with the wind. It took 12 hours. The trip back was into the wind. The trip back took 24 hours. We need to find What is the speed of the plane in still air? What is the speed of the wind? Let's find out :

For Going trip :

Let speed of plane be u , and wind be v so : Speed = ( Distance ) / ( time )

⇒ $u+v = \frac{1248}{12}$