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levacccp [35]
3 years ago
11

Grace works from 10 to 20 hours per week while attending college. She earns $9.00 per hour. The function e(h) represents her ear

nings each week . Describe an appropriate domain of this function
Mathematics
1 answer:
DerKrebs [107]3 years ago
3 0

Solution: The function that represents the Grace earning each week is defined as e(h)=9h, where e(h) is in dollar and h is the time in hours. domain of the function e(h)=9h is [10,20].

Explanation:

Let, Grace works for h hours per week.

For one hour she get $9.

For h hours she get \$(9\times h)=\$9h.

So, the function that represents the Grace earning each week is defined as e(h)=9h.

It is given that she works from 10 to 20 hours per week, therefore the value of h lies between 10 to 20. Hence the Grace's earnings for each week is defined as e(h)=9h and the domain of the function e(h)=9h is [10,20].

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Step-by-step explanation:

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Answer:

y = 3\left(x-\dfrac{3}{2}\right)^2+\dfrac{41}{4}

Step-by-step explanation:

Given equation:

y = 3x^2 - 9x + 17

Factor out 3 from the first 2 terms:

y = 3(x^2 - 3x) + 17

Divide the coefficient of x by 2 and square it:  (-3 ÷ 2)² = 9/4

Add this inside the parentheses and subtract the distributed value of it outside the parentheses:

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2 years ago
A t-shirt increased in price by 1/4. After the increase it was £20. What was the original price of the t-shirt?
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8 0
3 years ago
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A university researcher wants to estimate the mean number of novels that seniors read during their time in college. An exit surv
lys-0071 [83]

Answer:

Population mean = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

Step-by-step explanation:

Given - A university researcher wants to estimate the mean number

            of  novels that seniors read during their time in college. An exit

            survey was conducted with a random sample of 9 seniors. The

            sample mean was 7 novels with standard deviation 2.29 novels.

To find - Assuming that all conditions for conducting inference have

              been met, which of the following is a 94.645% confidence

              interval for the population mean number of novels read by

              all seniors?

Proof -

Given that,

Mean ,x⁻ = 7

Standard deviation, s = 2.29

Size, n = 9

Now,

Degrees of freedom = df

                                = n - 1

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⇒Degrees of freedom = 8

Now,

At 94.645% confidence level

α = 1 - 94.645%

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Now,

\frac{\alpha}{2} = \frac{0.05}{2}

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Then,

t_{\frac{\alpha}{2}, df }  = 2.306

∴ we get

Population mean = x⁻ ± t_{\frac{\alpha}{2}, df } ×\frac{s}{\sqrt{n} }

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⇒Population mean = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

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3 years ago
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