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levacccp [35]
3 years ago
11

Grace works from 10 to 20 hours per week while attending college. She earns $9.00 per hour. The function e(h) represents her ear

nings each week . Describe an appropriate domain of this function
Mathematics
1 answer:
DerKrebs [107]3 years ago
3 0

Solution: The function that represents the Grace earning each week is defined as e(h)=9h, where e(h) is in dollar and h is the time in hours. domain of the function e(h)=9h is [10,20].

Explanation:

Let, Grace works for h hours per week.

For one hour she get $9.

For h hours she get \$(9\times h)=\$9h.

So, the function that represents the Grace earning each week is defined as e(h)=9h.

It is given that she works from 10 to 20 hours per week, therefore the value of h lies between 10 to 20. Hence the Grace's earnings for each week is defined as e(h)=9h and the domain of the function e(h)=9h is [10,20].

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A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set w
VashaNatasha [74]

Complete Question

A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set was split into 5 segments (each 6.4 seconds long), what is the resulting:

a)F minimum

b) F maximum

c) Frequency resolution

Answer:

a) Fmax=100Hz

b) Fmin=0Hz

c) F_r=0.0313

Step-by-step explanation:

From the question we are told that:

Time t=32sec

FrequencyF=200Hz

Segments \mu=5

Generally the equation for Frequency Range is mathematically given by

Fmax=\frac{F}{2}

Fmax=100Hz

Therefore

a) Fmax=100Hz

b) Fmin=0Hz

c)

Generally the equation for Frequency Resolution is mathematically given by

F_r=\frac{F}{N}

Where

N=The Total dat points

N=Sampling Frequency *Time

N=200*32

N=6400

Therefore

F_r=\frac{200}{6400}

F_r=0.0313

6 0
3 years ago
Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!
il63 [147K]

Answer:

x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

Step-by-step explanation:

w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

6 0
3 years ago
What is the solution set to, "Katie wants to collect over 100 seashells. She already has 34 seashells in her collection. Each da
Anastaziya [24]

Answer:

Katie will collect more than 100 seashells in 5 and a half days.

Step-by-step explanation:

Katie already has 34 seashells in her collection.

Each day, she finds 12 more seashells on the beach.

Let x be the number of days Katie is collecting seashells.

In x days, she will collect 12x seashells.

In total, she will collect 34+12x seashells.

Katie wants to collect over 100 seashells, so

34+12x> 100

Solve this inequality. Subtract 34:

34+12x-34>100-34\\ \\12x>66\\ \\2x>11\\ \\x>5 \dfrac{1}{2}

Katie will collect more than 100 seashells in 5 and a half days.

3 0
3 years ago
math problme After hearing of the national result that 44% of students engage in binge drinking (5 drinks at a sitting for men,
natali 33 [55]

Answer:

According to the result of the hypothesis test, there is no significant difference between the true population proportion of students who binge drink according to the results of the Professor's survey and the national standard of 0.44.

So, the Professor shouldn't be surprised by this result.

Step-by-step explanation:

- The known standard proportion of students for binge drinking is 44% = 0.44.

- In the Professor's random sample, 96 out of 244 students admitted to binge drinking in the past week.

- So, we need to check if the result of the random sample is in keeping with the known national standard.

For hypothesis testing, the first thing to define is the null and alternative hypothesis.

The null hypothesis plays the devil's advocate and usually takes the form of the opposite of the theory to be tested. It usually contains the signs =, ≤ and ≥ depending on the directions of the test.

While, the alternative hypothesis usually confirms the the theory being tested by the experimental setup. It usually contains the signs ≠, < and > depending on the directions of the test.

For this question, the null hypothesis is that there is no significant difference between the true population proportion of students who binge drink according to the results of the Professor's survey and the national standard of 0.44.

The alternative hypothesis will now be that there is significant difference between the true population proportion of students who binge drink according to the results of the Professor's survey and the national standard of 0.44.

Mathematically,

The null hypothesis is represented as

H₀: p = 0.44

The alternative hypothesis is given as

Hₐ: p ≠ 0.44

To do this test, we will use the t-distribution because no information on the population standard deviation is known

So, we compute the t-test statistic

t = (x - μ)/σₓ

x = sample proportion of the Professor's poll = (96/244) = 0.393

μ = p₀ = the national standard = 0.44

σₓ = standard error = √[p(1-p)/n]

where n = Sample size = 244

σₓ = √[0.393×0.607/244] = 0.0313

t = (0.393 - 0.44) ÷ 0.0313

t = -1.50

checking the tables for the p-value of this t-statistic

Degree of freedom = df = n - 1 = 244 - 1 = 243

Significance level = 0.05 (most tests are performed at 5% significance level)

The hypothesis test uses a two-tailed condition because we're testing in the two directions.

p-value (for t = -1.50, at 0.05 significance level, df = 243, with a two tailed condition) = 0.134913

The interpretation of p-values is that

When the (p-value > significance level), we fail to reject the null hypothesis and when the (p-value < significance level), we reject the null hypothesis and accept the alternative hypothesis.

So, for this question, significance level = 0.05

p-value = 0.134913

0.134913 > 0.05

Hence,

p-value > significance level

This means that we fail to reject the null hypothesis & say that there is not enough evidence to conclude that there is a significant difference between the true population proportion of students who binge drink according to the Professor's survey and the national standard.

That is, there is no significant difference between the true population proportion of students who binge drink according to the results of the Professor's survey and the national standard of 0.44.

Hope this Helps!!!

8 0
3 years ago
Identify whether each scenario would be represented by a continuous or discrete graph
serg [7]

Answer: Identify whether each scenario would be represented by a continuous or discrete graph

Step-by-step explanation:

4 0
3 years ago
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