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maw [93]
3 years ago
11

To create a program in Scratch, you need to think systematically about the order of steps. This is known as

Computers and Technology
1 answer:
Katarina [22]3 years ago
4 0
Sequence. I took the same test like 5 minutes ago and got a perfect score
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To add a glow effect to WordArt text, which of the following should be done?
g100num [7]
Number 2 is the correct answer
8 0
3 years ago
SHOW ALL YOUR WORK. REMEMBER THAT PROGRAM SEGMENTS ARE TO BE WRITTEN IN JAVA. Assume that the classes listed in the Java Quick R
Ne4ueva [31]

Answer:

Check the explanation

Explanation:

CODE:-

import java.util.*;

class UserName{

  ArrayList<String> possibleNames;

  UserName(String firstName, String lastName){

      if(this.isValidName(firstName) && this.isValidName(lastName)){

          possibleNames = new ArrayList<String>();

          for(int i=1;i<firstName.length()+1;i++){

              possibleNames.add(lastName+firstName.substring(0,i));

          }  

      }else{

          System.out.println("firstName and lastName must contain letters only.");

      }

  }

  public boolean isUsed(String name, String[] arr){

      for(int i=0;i<arr.length;i++){

          if(name.equals(arr[i]))

              return true;

      }

      return false;

  }

  public void setAvailableUserNames(String[] usedNames){

      String[] names = new String[this.possibleNames.size()];

      names = this.possibleNames.toArray(names);

      for(int i=0;i<usedNames.length;i++){

          if(isUsed(usedNames[i],names)){

              int index = this.possibleNames.indexOf(usedNames[i]);

              this.possibleNames.remove(index);

              names = new String[this.possibleNames.size()];

              names = this.possibleNames.toArray(names);

          }

      }

  }

  public boolean isValidName(String str){

      if(str.length()==0) return false;

      for(int i=0;i<str.length();i++){

          if(str.charAt(i)<'a'||str.charAt(i)>'z' && (str.charAt(i)<'A' || str.charAt(i)>'Z'))

              return false;

      }

      return true;

  }

  public static void main(String[] args) {

      UserName person1 = new UserName("john","smith");

      System.out.println(person1.possibleNames);

      String[] used = {"harta","hartm","harty"};

      UserName person2 = new UserName("mary","hart");

      System.out.println("possibleNames before removing: "+person2.possibleNames);

      person2.setAvailableUserNames(used);

      System.out.println("possibleNames after removing: "+person2.possibleNames);

  }

}

Kindly check the attached image below for the code output.

5 0
4 years ago
Consider an error-free 64 kbps satellite channel used to send 512 byte data frames in one direction, with very short acknowledge
Vladimir [108]

Answer:

The answer is "2".

Explanation:

In the given question some information is missing, that is "The propagation time for satellite to earth" which is "270 milliseconds" so, the description to this question can be defined as follows:

Given values:

Bandwidth = 64 kbps

Data frames = 512 bytes  

Propagation Time (t​​​​​​p ) =270 ms

Change Bandwidth  kbps to bps:

1 kb= 1024 bytes

calculated bandwidth= 64 kbps = 64×1024 bps = 65536 bps

1 bytes = 8 bits

512 bytes = 512 × 8 =  4096 bits

Frame length = 4096 bits

Formula

Transmission time (T​​​​​​t) = Frame length /Bandwidth

Window size = 1+2a

where a = Propagation time/Transmission time

Calculate Transmission time:

Transmission time (T​​​​​​t) = 4096 / 65536

Transmission time (T​​​​​​t)= 625 m.sec

Calculate Window size:

Window size = 1+2(270/625)

Window size = 1+2(0.432)

Window size = 1+0.864

Window size = 1.864

Window size = 2

3 0
3 years ago
Mario was surprised that the box that was supposed to tell him how many words he used in his document did not appear after the s
Nookie1986 [14]

Answer:

Click the Display tab

Explanation:

Choose the Word count option to make it visible, within the Display tab dropdown

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3 years ago
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Do you think I should ask out myrandaduro2005
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Answer:

If you want, your choice

3 0
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Read 2 more answers
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