Barium chloride is salt with ionic bonds. Barium chloride contains one barium cations (charge of ion is 2+) and two chlorine anions (charge for ion is 1-).
The representative particle<span> of an ionic compound is its formula unit (</span>lowest whole number ratio of ions in an ionic compound), for barium chloride that is BaCl₂.
Explanation:
check the steps in the attached image
At 50 degrees Celsius and standard pressure inter-molecular forces of attraction are strongest in a sample of ethanoic acid.
Ethanoic acid has hydrogen atom bonded with a more electronegative atom; Oxygen. As a result, the molecule possesses strong intermolecular Hydrogen Bonds. Therefore; ethanoic acid, and all other carboxyllic acids have the tendency to form dimers.
Answer:
This question lacks options, the options are:
A). synthesizes more sugar
B). has a higher chromosome count
C). produces fewer proteins
D). uses less carbon dioxide
The answer is A
Explanation:
The chloroplast is an organelle present in the cells of photosynthetic organisms. It is the site where photosynthesis, which is the production of food (sugars) from sunlight energy, occurs.
According to this question, a cell in the leaf of a corn plant contains more chloroplasts than a cell in the stem of the same corn plant. Based on this observation, it can be inferred that the LEAF CELLS WILL SYNTHESIZE MORE SUGARS THAN THE STEM CELL because the more the chloroplast, the higher the photosynthetic rate and subsequently the higher the amount of sugar produced.
Answer:
![V=27992L=28.00m^3](https://tex.z-dn.net/?f=V%3D27992L%3D28.00m%5E3)
Explanation:
Hello,
In this case, the combustion of methane is shown below:
![CH_4+2O_2\rightarrow CO_2+2H_2O](https://tex.z-dn.net/?f=CH_4%2B2O_2%5Crightarrow%20CO_2%2B2H_2O)
And has a heat of combustion of −890.8 kJ/mol, for which the burnt moles are:
![n_{CH_4}=\frac{-1.00x10^6kJ}{-890.8kJ/mol}= 1122.6molCH_4](https://tex.z-dn.net/?f=n_%7BCH_4%7D%3D%5Cfrac%7B-1.00x10%5E6kJ%7D%7B-890.8kJ%2Fmol%7D%3D%201122.6molCH_4)
Whereas is consider the total released heat to the surroundings (negative as it is exiting heat) and the aforementioned heat of combustion. Then, by using the ideal gas equation, we are able to compute the volume at 25 °C (298K) and 745 torr (0.98 atm) that must be measured:
![PV=nRT\\\\V=\frac{nRT}{P}=\frac{1122.6mol*0.082\frac{atm*L}{mol*K}*298K}{0.98atm}\\\\V=27992L=28.00m^3](https://tex.z-dn.net/?f=PV%3DnRT%5C%5C%5C%5CV%3D%5Cfrac%7BnRT%7D%7BP%7D%3D%5Cfrac%7B1122.6mol%2A0.082%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D%2A298K%7D%7B0.98atm%7D%5C%5C%5C%5CV%3D27992L%3D28.00m%5E3)
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