Answer:
x=10
Step-by-step explanation:
the angle is 90 degrees
90-29=61
61-1=60
60÷6=5
x=10
have a good day
Answer:
y = -1
Step-by-step explanation:
Any ordinate pair (x, y) represents the input output values of a function to be graphed.
For any input value of x, there will be an output value (y).
If input value for the graph attached is x = 0,
Output value will be represented by the y-value along y-axis as, y = -1
Therefore, y = -1 will be the answer.
The answer's 2.2
I'm sorry I can't show you, but LaTex doesn't allow you to show short division.
You can find out how to do it here, on Wikipedia's page. https://www.wikiwand.com/en/Short_division
Answer:
We need a sample of size at least 13.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

90% confidence interval: (0.438, 0.642).
The proportion estimate is the halfway point of these two bounds. So

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Using the information above, what size sample would be necessary if we wanted to estimate the true proportion to within ±0.08 using 95% confidence?
We need a sample of size at least n.
n is found when M = 0.08. So






Rounding up
We need a sample of size at least 13.