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bazaltina [42]
3 years ago
15

Can someone help me please

Mathematics
1 answer:
Oxana [17]3 years ago
5 0
C

3 3/4 = 3.75
21/6 = 3.5
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Deane is flying to a destination that is 2745 miles away. The plane's average speed is 450 mph. Write the slope-intercept form o
Dmitriy789 [7]
The equation in y = mx+b form is y = -450x+2745

where,
x = number of hours that have passed by
y = distance to destination in miles

The y intercept is 2745 since this is the initial starting y value, aka the starting distance. Therefore b = 2745.

The slope is -450 or -450/1 since for each hour, the distance goes down by 450. You can think of it as
slope = (change in y)/(change in x)
slope = (change in distance)/(change in time)
slope = (-450 miles)/(1 hour)
slope = -450
8 0
3 years ago
Expand the following expression
masya89 [10]

Answer:

\frac{5}{4}  \times 4x +  \frac{5}{4}  \times  \frac{3}{4}  = 5x +  \frac{15}{16}

5 0
3 years ago
Can someone solve this please
grandymaker [24]

Answer:15. 5/8 = 0.625

Step-by-step explanation:

5 0
3 years ago
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters,
valentinak56 [21]

Answer:

The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample  means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean  is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

<em>μ</em> = 144 mm

<em>σ</em> = 7 mm

<em>n</em> = 50.

Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

\bar X\sim N(\mu_{\bar x}=144, \sigma_{\bar x}^{2}=0.98)

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})

                           =P(Z>2.63)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

8 0
3 years ago
Tatiana is practicing shooting. The coordinates (in m) of the barrel of her gun and the target are (5, 3, 1) and (38, 41, 3). Wh
saul85 [17]

Answer:

d=\sqrt{2,537}\ m   or  d=50.37\ m

Step-by-step explanation:

we know that

the formula to calculate the distance between two points in three dimensions is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}+(z2-z1)^{2}}

Let

A(5,3,1)  -----> coordinates of the barrel of her gun

B(38,41,3)  -----> coordinates of the target

substitute the values

d=\sqrt{(41-3)^{2}+(38-5)^{2}+(3-1)^{2}}

d=\sqrt{(38)^{2}+(33)^{2}+(2)^{2}}

d=\sqrt{1,444+1,089+4}

d=\sqrt{2,537}\ m

d=50.37\ m

7 0
3 years ago
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