Well, your question is basically;
x²+6x+5
Well first you have to find two numbers that when added will give you +6 and when multiplied will give you 5. Well, in this case, the numbers are; (+1 and +5). So you add them to the equation. So;
x²+1x+5x+5
Hope you noticed that 6x was removed. Anyway;
You have to put the equation in two brackets with two terms in each
(x²+1x)+(5x+5)
Next, you bring out what is commom in each bracket and use it to divide what is in the bracket
x(x+1)+5(x+1)
Now you notice that the two things in the bracket are the same. They have to be.
Next, you put the terms outside the bracket together and choose one of the terms in a bracket. So;
(x+5) (x+1)
So the equation factorised is (x+5) (x+1). But if you want to go ahead to find x, then you can say;
(x+5) (x+1)
x+5=0 x+1=0
Take the +5 over Take the +1 over the equal to, where it becomes -1. So;
the equal sign where x=-1
it becomes -5. So;
x=-5 OR x=-1
By the way, here's a little secret, the answers are always the opposite of the two numbers chosen at the beginning(+1 and +5). Hope i helped. If you have any more problems, let me know.
Answer: i think it’s A and D
To solve this, we would need to figure out the values of 
for which an absolute value is negative. From basics, you should know that an absolute value is always greater than or equal to 0.
If we rearrange this equation a little bit, we get,
So 
<em>cannot </em>be negative. So,
For this to <em>have </em>a solution, k needs to be greater than or equal to 
.
For <em>no solution</em>, k is less than -5. So, values of k which will make the equation to <em>not </em>have any solution is 
.
ANSWER:
I don’t know what the question is, your just saying that
