Answer:
Choice C.
Step-by-step explanation:
Choice C has the most numbers close together, and not far away like an outlier.
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D.6, 7, 5, 8, 9, 1
A.25, 33, 29, 31, 33, 33, 78, 28 78 is an outlier
B.101, 99, 98, 111, 11, 101, 103 11 is an outlier
C.45, 45, 45, 45, 35, 45 35 is an outlier
D.6, 7, 5, 8, 9, 1 no outliers the numbers are within 1.5 of the IQR
12 (2+3)
You will find the GCF of 24 and 36 which is 12
126 apples
Let the number of apples picked by Mary=m
Cindy picks 6 times as many as Mary= 6Xm=6m
John picks 8 times as many as Mary= 8Xm=8m
Altogether they picked a total of 135 apples.
m+6m+8m=135
15m=135
m=135/15
m=9
We want to determine how many apples John and Cindy Picked.
John Picked 6m apples
Cindy Picked 8m apples
Their combined total= 6m+8m =14m
Since m=9
14m =14 X9 =126 apples
John and Cindy picked a total of 126 apples
The number of ways to select a sample of 2 computer chips so that at least one of the chips is defective is 33 ways.
The box contains 13 computer chips. Of these 13 chips 3 are defective and 10 are good.
A quality control inspector samples 2 computer chips.
The number of ways to select at least 1 defective chip is:
n (At least 1 defective chip) = n (1 defective chip) + n (2 defective chips)
The number of ways to select 1 defective chip is: ways.
The number of ways to select 2 defective chips is: ways.
= 30 + 3
= 33
Thus, the number of ways to select a sample of 2 computer chips so that at least one of the chips is defective is 33 ways.