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vekshin1
3 years ago
12

PLEASE HELP!!!!!!! Which of the following sets of data does not contain an outlier? A.25, 33, 29, 31, 33, 33, 78, 28 B.101, 99,

98, 111, 11, 101, 103 C.45, 45, 45, 45, 35, 45 D.6, 7, 5, 8, 9, 1
Mathematics
2 answers:
lesantik [10]3 years ago
5 0

Answer:

Choice C.

Step-by-step explanation:

Choice C has the most numbers close together, and not far away like an outlier.

Please mark me BRAINLIEST! Thanks!

docker41 [41]3 years ago
3 0

Answer:

D.6, 7, 5, 8, 9, 1

Step-by-step explanation:

A.25, 33, 29, 31, 33, 33, 78, 28   78 is an outlier

B.101, 99, 98, 111, 11, 101, 103           11 is an outlier

C.45, 45, 45, 45, 35, 45    35 is an outlier

D.6, 7, 5, 8, 9, 1   no outliers  the numbers are within 1.5 of the IQR

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Natural numbers are counting numbers. Natural numbers cannot be a fraction with a different numerator and denominator when simplified. Therefore 2/5 is not a natural number.
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3 years ago
Simplify: 24 + 36 using the distributive property.
Advocard [28]

Answer:

12 (2+3)

Step-by-step explanation:

You will find the GCF of 24 and 36 which is 12

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Cindy pics six times as many apples as Mary John pick eight times as many apples as Mary together they picked 135 apples how man
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Answer:

126 apples

Step-by-step explanation:

Let the number of apples picked by Mary=m

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John picks 8 times as many as Mary= 8Xm=8m

Altogether they picked a total of 135 apples.

m+6m+8m=135

15m=135

m=135/15

m=9

We want to determine how many apples John and Cindy Picked.

John Picked 6m apples

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Their combined total= 6m+8m =14m

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14m =14 X9 =126 apples

John and Cindy picked a total of 126 apples

3 0
3 years ago
A quality control inspector samples 2 computer chips from a box containing 13 computer chips. If the box contains 3 defective ch
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Answer:

The number of ways to select a sample of 2 computer chips so that at least one of the chips is defective is 33 ways.

Step-by-step explanation:

The box contains 13 computer chips. Of these 13 chips 3 are defective and 10 are good.

A quality control inspector samples 2 computer chips.

The number of ways to select at least 1 defective chip is:

n (At least 1 defective chip) = n (1 defective chip) + n (2 defective chips)

The number of ways to select 1 defective chip is: {3\choose 1}{10\choose 1}=3\times10=30 ways.

The number of ways to select 2 defective chips is:{3\choose 2}{10\choose 0}=3\times1=3 ways.

n (At least 1 defective chip) = n (1 defective chip) + n (2 defective chips)

                                             = 30 + 3

                                             = 33

Thus, the number of ways to select a sample of 2 computer chips so that at least one of the chips is defective is 33 ways.

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Multiply 3x-4y=-2 by three numbers and see if (6,5) is still a solution
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18-20 = -2
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so yes (6,5) is a solution.
6 0
3 years ago
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