Ask question

Ask question

All categories

1 year ago

12

A man walking his dog along a Straight road spots a friend a mile away. They wave at one another and the dog sprints to greet he

r. As soon as the dog arrives it turns around and runs straight back to its master. Then turns around again and runs back to the girl, who is, of course, nearer now. The dog continues running backs and forth until the two meet. Given that each person walks at a steady 3 mph, and the dog runs a steady 9 mph, what is the total distance the dog runs?

1 answer:

steposvetlana [31]1 year ago

7 0

The distance the dog runs is given by the time it takes the man and the

girl to meet multiplied by the speed of the dog.

Correct response:

The total distance the dog runs is <u>1.5 miles</u>

<h3>How to find the distance ran by the dog</h3>

Given parameters;

Initial distance of the friend away = 1 mile

Speed of the man = 3 mph

Speed of the girl = 3 mph

Speed of the dug = 9 mph

Required:

The total distance the dog runs

Solution:

$Time = \mathbf{\dfrac{Distance}{Speed}}$

The time it takes the man and the girl to meet, <em>t</em>, is given as follows;

$t = \dfrac{1 \ mile}{3 \ mph + 3 \ mph} = \mathbf{\dfrac{1}{6} \, hours}$

Therefore;

$The \ total \ distance \ dog \ runs, \ d = 9 \ mph \times \dfrac{1}{6} \, hours = \underline{ 1.5 \, miles}$

Learn more about velocity and speed here:

brainly.com/question/4130932

You might be interested in

7+4u=70-3u<br> What is U

ruslelena [56]

$7+4u=70-3u \\ 7+4u+3u=70-3u+3u \\ 7+7u=70 \\ 7-7+7u=70-7 \\ 7u=63 \\ 7u/7=63/7 \\ u=9$
u=9 is your answer.
Hope this helps!

5 0

2 years ago

Read 2 more answers

Help me yall!!......

Ugo [173]

This then allows us to see exactly how and where the subtended angle θ of a sector will fit into the sector formulas. Now we can replace the "once around" angle (that is, the 2π) for an entire circle with the measure of a sector's subtended angle θ, and this will give us the formulas for the area and arc length of that sector

8 0

2 years ago

PLEASE HELP ME QUICK!!

9966 [12]

Answer: yes kevin skied as long as lori

3 0

1 year ago

Which property applies only to addition and multiplication

True [87]

The property the applies only to addition and multiplication is the commutative property. It means that the numbers can be arranges in any order. so for example you will get the same answer whether you do
5+6 or 6+5

6 0

2 years ago

Read 2 more answers

Condensing Logarithmic Expressions In Exercise, use the properties of logarithms to rewrite the expression as the logarithm of a

yKpoI14uk [10]

Answer:

$4ln [\frac{x^2 (x^3-1)}{x-5}]$

Step-by-step explanation:

For this case we have the following expression:

$4[ln(x^3-1) +2ln(x) -ln(x-5)]$

For this case we can apply the following property:

$a log_c (b) = log_c (b^a)$

And we can rewrite the following expression like this:

$2 ln(x) = ln(x^2)$

And we can rewrite like this our expression:

$4[ln(x^3-1) +ln(x^2) -ln(x-5)]$

Now we can use the following property:

$log_c (a) +log_c (b) = log_c (ab)$

And we got this:

$4[ln(x^3-1)(x^2) -ln(x-5)]$

And now we can apply the following property:

$log_c (a) -log_c (b) = log_c (\frac{a}{b})$

And we got this:

$4ln [\frac{x^2 (x^3-1)}{x-5}]$

And that would be our final answer on this case.

8 0

2 years ago