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Mumz [18]
3 years ago
11

Graph the function. h(x) = x^2 + 2x

Mathematics
1 answer:
andrew11 [14]3 years ago
7 0
This is the right answer

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What is the nearest whole percent of 62
charle [14.2K]
The nearest whole percent would just be 62%
4 0
3 years ago
Read 2 more answers
??????????????????????
gtnhenbr [62]

Answer:

110 degrees

Step-by-step explanation:

I don't know if that is correct.

6 0
3 years ago
Slove for y show all your work 12y + 4 = 8y-12​
Vedmedyk [2.9K]

Answer:

y = -4

Step-by-step explanation:

12y + 4 = 8y-12​

Subtract 8y from each side

12y - 8y +4 = -12

4y +4 = -12

Subtract 4 from each side

4y +4-4 = -12 -4

4y = -16

Divide by 4

4y/4 = -16/4

y = -4

8 0
3 years ago
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Trina planted plants in her garden last week. She planted twice as many cucumbers as zucchini and eight more tomatoes than cucum
maxonik [38]

Answer:

7 Zuchini, 14 Cucumbers and 22 Tomatoes plants.

Step-by-step explanation:

  • Let the number of tomatoes=t
  • Let the number of cucumber planted=c
  • Let the number of zucchini planted=z
  • Total Number of Plants=43

She planted twice as many cucumbers as zucchini, this is written as:

  • c=2z

She also planted eight more tomatoes than cucumbers, this is written as:

  • t=c+8=2z+8

In total, she planted 43 plants

Therefore:

z+(2z)+(2z+8)=43

5z+8=43

5z=43-8

5z=35

Divide both sides by 5

z=7

Number of Cucumbers, c=2z=2 X 7 =14

Number of Tomatoes, t=c+8=14+8=22

Therefore, she planted 7 Zuchini, 14 Cucumbers and 22 Tomatoes plants.

3 0
3 years ago
A Cepheid variable star is a star whose brightness alternately increases and decreases. For a certain star, the interval between
victus00 [196]

Answer:

a) \frac{dB}{dt} = \frac{5\pi}{4.2} \cdot \cos \left(2\pi\cdot \frac{t}{4.2} \right), b) \frac{dB}{dt}\approx 5.595

Step-by-step explanation:

a) The rate of change of the brightness of the Cepheid can be determined by deriving the function in time:

\frac{dB}{dt} = \left(\frac{2\pi}{4.2} \right)\cdot 0.25\cdot \cos (2\pi\cdot \frac{t}{4.2})

\frac{dB}{dt} = \frac{5\pi}{4.2} \cdot \cos \left(2\pi\cdot \frac{t}{4.2} \right)

b) The rate of increase after one day is:

\frac{dB}{dt} = \frac{5\pi}{4.2} \cdot \left(2\pi \cdot \frac{1}{4.2} \right)

\frac{dB}{dt}\approx 5.595

4 0
3 years ago
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