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Firdavs [7]
3 years ago
7

Hannah is a photographer who specializes in portraits. This morning, she soent four hours doing graduation portrait sessions. In

the afternoon, she soent four hours doing family portaits sessions but she didnt do as many session as the graduation portraits. Tomorrow, she has the same number of graduation and family sessions to work. Which will she likely finish in less time?
Mathematics
1 answer:
FromTheMoon [43]3 years ago
7 0
She will likely finish the graduation sessions in less time.
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Square EFGH stretches vertically by a factor of 2.5 to create rectangle E′F′G′H′. The square stretches with respect to the x-axi
Kaylis [27]

Answer:

The coordinates of point H' are (-2 , 0) ⇒ answer B

Step-by-step explanation:

* <em>Lets revise the vertical stretch</em>

- A vertical stretching is the stretching of the graph away from the  

 x-axis  

- If k > 1, then the graph of y = k • f(x) is the graph of f(x) vertically

 stretched by multiplying each of its y-coordinates by k

* <em>Lets solve the problem</em>

- Square EFGH stretches vertically by a factor of 2.5 to create

 rectangle E′F′G′H′

∴ k = 2.5

- The square stretches with respect to the x-axis

∴ The square stretches vertically

∴ The <u>y-coordinates</u> of each vertex of the square EFGH are

  multiplied by <u>2.5</u> to get the vertices of the rectangle E'F'G'H'

∵ Point H located at (-2 , 0)

∵ The image of point (x , y) after stretched vertically by k is (x , ky)

∴ Point H' located at (-2 , 0 × 2.5) ⇒ (-2 , 0)

∴ The coordinates of point H' are (-2 , 0)

∴ Point H' located at (-2 , 0)

7 0
3 years ago
HELP ME PLS
kolbaska11 [484]

<u>Answer:</u>

Slope = 27/11

AB = 29.15 u

<u>Step-by-step explanation:</u>

<u>Given :- </u>

  • Two points are given to us .
  • The points are A(7,15) and B(18,42)

<u>To Find :- </u>

  • The slope of the line .
  • The length of line AB .

We can find the slope of the line passing through the points ( x_1,y_1) and ( x_2,y_2)as ,

\implies m = \dfrac{ y_2-y_1}{x_2-x_{1}}

  • Plug in the respective values ,

\implies m = \dfrac{ 42-15}{18-7} \\\\\implies \boxed{ m = \dfrac{ 27}{11 }}

<u>Hence the slope of the line is 27/11 .</u>

\rule{200}2

<u>Finding the length of AB :-</u>

  • We can find the distance between them by using the Distance Formula .

\implies Distance =\sqrt{ (x_2-x_1)^2+(y_2-y_1)^2} \\\\\implies Distance =\sqrt{ (18-7)^2+(42-15)^2 }  \\\\\implies Distance =\sqrt{ 11^2 + 27^2 } \\\\\implies Distance =\sqrt{ 121 + 729 } \\\\\implies Distance = \sqrt{ 850} \\\\\implies \boxed{ Distance = 29.15 \ units }

<u>Hence the length of AB is 29.15 units </u>.

5 0
3 years ago
Which of the following binomials is a factor of x^3+4x^2+x-6
larisa [96]
The answer could be 3, 2, or 1
5 0
3 years ago
Find the area of the figure.
Arisa [49]

Answer:

can u clarify bc area is 2 but 4 things is perimiter

Step-by-step explanation:

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3 years ago
Identify the x-intercept
sveta [45]

im quite positive that the x-intercept is 1,6

8 0
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