Answer:
The tension in the part of the cord attached to the textbook is 6.58 N.
Explanation:
Given that,
Mass of textbook = 2.09 kg
Diameter = 0.190 m
Mass of hanging book = 3.08 kg
Distance = 1.26 m
Time interval = 0.800 s
Suppose,we need to calculate the tension in the part of the cord attached to the textbook
We need to calculate the acceleration
Using equation of motion


Put the value into the formula


We need to calculate the tension
When the book is moving with acceleration
Using formula of tension



Hence, The tension in the part of the cord attached to the textbook is 6.58 N.
Well, neutering a cat will not keep it from running away.
Answer:
momentum in a body can be calculated using
<em><u>Mome</u></em><em><u>ntum</u></em><em><u>=</u></em><em><u>Mass×</u></em><em><u>V</u></em><em><u>e</u></em><em><u>l</u></em><em><u>o</u></em><em><u>s</u></em><em><u>i</u></em><em><u>t</u></em><em><u>y</u></em><em><u> </u></em>
<em><u>i</u></em><em><u>e(</u></em><em><u>p</u></em><em><u>=</u></em><em><u>m×</u></em><em><u>v</u></em><em><u>)</u></em>
Answer:
0.08
Explanation:
this problem assume that both of whale and submarine are in rest position or in constant linier motion in same direction and same speed.
The sound will travel from Submarine to the whale and back again to submarine. so the time will be like this
t = 2d/v
t = 2*58.8/1520
t = 117.6/1520
t = 0.077368 s
t ≈ 0.08 s (less then 1 s)
True. No matter can be created nor destroyed in pretty much every aspect of life, especially chemical reactions.