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4 years ago

By listening to an orchestra, how can you determine that the speed of sound is the same for all frequencies?

Physics

1 answer:

Alisiya [41]4 years ago

6 0

You hear it all simultaneously in<span> your ear at the same time.</span>

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Observe the given figure and find the the gravitational force between m1 and m2.

Leno4ka [110]

Answer:

The gravitational force between m₁ and m₂, is approximately 1.06789 × 10⁻⁶ N

Explanation:

The details of the given masses having gravitational attractive force between them are;

m₁ = 20 kg, r₁ = 10 cm = 0.1 m, m₂ = 50 kg, and r₂ = 15 cm = 0.15 m

The gravitational force between m₁ and m₂ is given by Newton's Law of gravitation as follows;

$F =G \cdot \dfrac{m_{1} \cdot m_{2}}{r^{2}}$

Where;

F = The gravitational force between m₁ and m₂

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

r₂ = 0.1 m + 0.15 m = 0.25 m

Therefore, we have;

$F = 6.67430 \times 10^{-11} \ N \cdot m^2/kg \times \dfrac{20 \ kg\times 50 \ kg}{(0.1 \ m+ 0.15 \ m)^{2}} \approx 1.06789 \times 10^{-6} \ N$

The gravitational force between m₁ and m₂, F ≈ 1.06789 × 10⁻⁶ N

8 0

3 years ago

What is the maximum m2 value that the system can be stationary at?

Ne4ueva [31]

Answer: 37.5 kg in 3 s.f.

Explanation:

7 0

3 years ago

An electron is released from rest in a uniform electric field of 418 N/C near a particle detector. The electron arrives at the d

Oksanka [162]

Answer:

a) 7.35 x 10¹³ m/s²

b) 5.03 x 10⁻⁸ sec

c) 9.3 cm

d) 6.23 x 10⁻¹⁸ J

Explanation:

E = magnitude of electric field = 418 N/C

q = magnitude of charge on electron = 1.6 x 10⁻¹⁹ C

m = mass of the electron = 9.1 x 10⁻³¹ kg

acceleration of the electron is given as

$a = \frac{qE}{m}$

$a = \frac{(1.6\times 10^{-19})(418)}{(9.1\times 10^{-31})}$

a = 7.35 x 10¹³ m/s²

v = final velocity of the electron = 3.70 x 10⁶ m/s

v₀ = initial velocity of the electron = 0 m/s

t = time taken

Using the equation

v = v₀ + at

3.70 x 10⁶ = 0 + (7.35 x 10¹³) t

t = 5.03 x 10⁻⁸ sec

d = distance traveled by the electron

using the equation

d = v₀ t + (0.5) at²

d = (0) (5.03 x 10⁻⁸) + (0.5) (7.35 x 10¹³) (5.03 x 10⁻⁸)²

d = 0.093 m

d = 9.3 cm

Kinetic energy of the electron is given as

KE = (0.5) m v²

KE = (0.5) (9.1 x 10⁻³¹) (3.70 x 10⁶)²

KE = 6.23 x 10⁻¹⁸ J

4 0

4 years ago

The proper IUPAC naming convention for the compound symbol 'KI' is

Darya [45]

Proablyly a or c idk

6 0

3 years ago

A 10kg object experiences a horizontal force which causes it to accelerate 5 m/s2 moving it a distance of 20 m horizontally. How

mr_godi [17]

Answer:

The work done by the force is 1000 J.

Explanation:

Given:

Mass of object (m) = 10 kg

Acceleration of the object (a) = 5 m/s²

Displacement of the object (S) = 20 m

Using Newton's second law, we have:

Force = Mass × Acceleration

$F=ma$

Plug in the given values and solve for force 'F' acting on the object. This gives,

$F=(10\ kg)(5\ m/s^2)\\\\F=50\ N$

Now, work done by the force 'F' is equal to the product of force 'F' and the displacement it cause in its direction which is 20 m.

Therefore, the work done by the force is given as:

Work = Force × Displacement

$W=FS$

Plug in the values given and solve for 'W'. This gives,

$W=50\ N\times 20\ m \\\\W=1000\ J$

Therefore, the work done by the force is 1000 J.

7 0

4 years ago