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2 years ago

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The pressure of a gas contained in a cylinder with a movable piston is 490 Pa. The area of the piston is 0.8 m2. Calculate the m

ass that is exerted on the piston.

1 answer:

andriy [413]2 years ago

8 0

Hello! Please answer my question that I just posted I really need answers. I don’t know sorry hope u fine someone that does know

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Alligators and other reptiles don't use enough metabolic energy to keep their body temperatures constant. They cool off at night

ANTONII [103]

Answer:

Explanation:

Amount of heat required can be found from the following relation

Q = mcΔT

m is mass of the body , c is specific heat and ΔTis rise in temperature .

Here m = 300 kg

c = 3350 J /kg k

ΔT = 30 - 25

= 5 °C

Putting the values in the expression above

Q = 300 x 3350 x 5

= 5025000 J

Rate at which energy is absorbed = 1200 J /s

Time required

= 5025000 / 1200

= 4187.5 S

= 69.8 minute

= 1 hour 9.8 mimutes.

4 0

2 years ago

Three identical very dense masses of 3500 kg each are placed on the x axis. One mass is at x1 = -100 cm , one is at the origin,

larisa86 [58]

Answer:

<em>A) 7.37 x 10^-4 N</em>

<em>B) The resultant force will be towards the -x axis</em>

Explanation:

The three masses have mass = 3500 kg

For the force of attraction between the mass at the origin and the mass -100 cm away:

distance r = 100 cm = 1 m

gravitational constant G= 6.67×10^−11 N⋅m^2/kg^2

Gravitational force of attraction $F_{g}$ = $\frac{Gm^{2} }{r^{2} }$

where G is the gravitational constant

m is the mass of each of the masses

r is the distance apart = 1 m

substituting, we have

$F_{g}$ = $\frac{6.67*10^{-11}*3500^{2} }{1^{2} }$ = 8.17 x 10^-4 N

For the force of attraction between the mass at the origin and the mass 320 cm away

distance r = 320 cm = 3.2 m

$F_{g}$ = $\frac{Gm^{2} }{r^{2} }$

substituting, we have

$F_{g}$ = $\frac{6.67*10^{-11}*3500^{2} }{3.2^{2} }$ = 7.98 x 10^-5 N

Resultant force = (8.17 x 10^-4 N) - (7.98 x 10^-5 N) = <em>7.37 x 10^-4 N</em>

<em></em>

<em>B) The resultant force will be towards the -x axis</em>

7 0

3 years ago

An inclined plane has a ramp length of 4.0 meters and a height of 2.0 meters. What is the IMA of the inclined plane? 0.5 2.0 6.0

Aleonysh [2.5K]

Length of the ramp (L) = 4.0 m = Distance traveled by the effort

Height of the inclined plane (h) = 2.0 m = Distance traveled by the resistance

IMA = Ideal mechanical advantage

$IMA = \frac{L}{h}$

$IMA = \frac{4.0}{2.0}$

IMA = 2.0

Hence, the IMA of the inclined plane is 2.0

6 0

2 years ago

An object accelerates at 10 m/s2. If its starting velocity is 20 m/s and it travels for 30 seconds, what is its final velocity?

polet [3.4K]

Answer:

320m/s

Explanation:

Step 1: State your values

s= NOT NEEDED

u=20m/s

v=?

a=10m/s²

t=30 seconds

Step 2: Find a suitable suvat equation:

v=u+at

Step 3:

subsitute values into equation:

?=20+(10x30)

20+300

320m/s

8 0

3 years ago

Departments A, B, and C have 10 employees each, and department D has 20 employees. Departments A, B, C, and D have no employees

juin [17]

Answer:

the answer is 10 task forces

Explanation:

A task force is composed for

A=1

B=1

C=1

D=2

if we form 10 work groups, we must multiply by 10 each quantity of workers

A=1x10, B=1x10, C=1x10,D=2x10

A=10, B=10, C=10, D=20

This is the total number of employees in all departments

6 0

3 years ago