Answer:
306.8 feet
Step-by-step explanation:
Refer the attached figure .
A surveyor moves 160 feet away from the base of the pole i.e. ED = 160 m
Referring the image .
AC=ED=160 m
A transit i.e. AE is 6 feet tall.
AE = CD=6 feet
With a transmit the angle of elevation to the top of the pole to be 62° i.e. ∠BAC = 62°
To Find BC , use tigonometric ratio.





Now, the height of the pole = BC+CD =300.8+6=306.8 feet
Hence the height of the pole is 306.8 feet
Answer:4000
Step-by-step explanation: becuase each would get 3000 and he got 1000 so 3000+1000=4000
Answer: 27x^5/250
Step-by-step explanation:
I assume that's a fraction on a fraction.
12x^3/25×40/9x^2 = (12x^3 × 9x^2)/1000
= 108x^5/100
= 27x^5/250
2(25)^x would be the correct equivalent function
Associative
** property I believe.