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jok3333 [9.3K]
4 years ago
11

Plz help. Attachment below

Mathematics
2 answers:
Vinvika [58]4 years ago
7 0

Answer:

The value of k is 1.

Step-by-step explanation:

You have to apply Indices Law :

{a}^{m}  \times  {a}^{n}  =  {a}^{m + n}

For this question :

{( \frac{4}{5} )}^{2}  \times  {( \frac{4}{5} )}^{5}  =  {( \frac{4}{5} )}^{6k + 1}

{( \frac{4}{5}) }^{2 + 5}  =  {( \frac{4}{5}) }^{6k + 1}

by \: comparison

2 + 5 = 6k + 1

7 = 6k + 1

7 - 1 = 6k

6k = 6

k = 6 \div 6

k = 1

Sergio039 [100]4 years ago
7 0

Answer:

k = 1

Step-by-step explanation:

a^{m} * a^{n} = a^{m+n}\\\\(\frac{4}{5})^{2}*(\frac{4}{5})^{5}=(\frac{4}{5})^{6k+1}\\\\\\(\frac{4}{5})^{2+5}=(\frac{4}{5})^{6k+1}\\\\(\frac{4}{5})^{7}=(\frac{4}{5})^{6k+1}

Compare the powers,

6k + 1 = 7         {subtract 1 from both sides}

     6k = 7 - 1

    6k  = 6     {Divide both sides by 6}

  6k/6= 6/6

k = 1

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