Given:
Base of a right triangle = 7 in
Height of a right triangle = a
Hypotenuse = 16 in
To find:
The length of side a.
Solution:
Using Pythagoras theorem:
Subtract 49 from both sides.
Taking square root on both sides, we get
a = 14.4
The length of side a is 14.4 in.
9514 1404 393
Answer:
B) y = 0.25x +5
Step-by-step explanation:
The x-value differ by 1, so the slope is the difference in y-values.
Comparing for x=2 and x=3, we see that the y-value increases by 0.25 from 0 to 0.25. This is the slope of the data in the table.
The equation with the same slope will have 0.25 as the x-coefficient. The equation of choice B is the one you're looking for.
y = 0.25x +5
_____
You don't care about the equation of the table, but it is ...
y = 0.25x -0.5
The answer to the question is A
Answer:
Option C. f(n) = 16(3/2)⁽ⁿ¯¹⁾
Step-by-step explanation:
To know which option is correct, do the following:
For Option A
f(n) = 3/2(n – 1) + 16
n = 1
f(n) = 3/2(1 – 1) + 16
f(n) = 3/2(0) + 16
f(n) = 16
n = 2
f(n) = 3/2(n – 1) + 16
f(n) = 3/2(2 – 1) + 16
f(n) = 3/2(1) + 16
f(n) = 3/2 + 16
f(n) = 1.5 + 16
f(n) = 17.5
For Option B
f(n) = 3/2(16)⁽ⁿ¯¹⁾
n = 1
f(n) = 3/2(16)⁽¹¯¹⁾
f(n) = 3/2(16)⁰
f(n) = 3/2 × 1
f(n) = 1
For Option C
f(n) = 16(3/2)⁽ⁿ¯¹⁾
n = 1
f(n) = 16(3/2)⁽¹¯¹⁾
f(n) = 16(3/2)⁰
f(n) = 16 × 1
f(n) = 16
n = 2
f(n) = 16(3/2)⁽ⁿ¯¹⁾
f(n) = 16(3/2)⁽²¯¹⁾
f(n) = 16(3/2)¹
f(n) = 16(3/2)
f(n) = 8 × 3
f(n) = 24
n = 3
f(n) = 16(3/2)⁽ⁿ¯¹⁾
f(n) = 16(3/2)⁽³¯¹⁾
f(n) = 16(3/2)²
f(n) = 16(9/4)
f(n) = 4 × 9
f(n) = 36
For Option D
f(n) = 8n + 8
n = 1
f(n) = 8(1) + 8
f(n) = 8 + 8
f(n) = 16
n = 2
f(n) = 8n + 8
f(n) = 8(2) + 8
f(n) = 16 + 8
f(n) = 24
n = 3
f(n) = 8n + 8
f(n) = 8(3) + 8
f(n) = 24 + 8
f(n) = 32
From the above illustration, only option C describes the sequence.
Answer:
s = 4 3/4.
Step-by-step explanation:
The formula is s = ut + 1/2 at^2
so s = 10^1/2 + 1/2 * -2 * (1/2)^2
s = 5 - 1/4
= 4 3/4.
