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Anvisha [2.4K]
3 years ago
5

In the summer, the Thomas family enjoys picking berries together. It takes them 20 minutes to pick 3 baskets of berries.

Mathematics
2 answers:
erastova [34]3 years ago
8 0

Answer:

the numbers 20, 60, 80, and 120 go on the x axis

the numbers, 3, 9, 12, and 18 go on the y axis

so you go to 20 on the bottom and go up to  number 3

60 go up to number 9

80 go up  to number 12

120 go up to  number 18

Step-by-step explanation:

ser-zykov [4K]3 years ago
3 0
What they said! lol :) ^
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If cos theta = 3/5 then tan theta =
algol13

Answer:

3 √5

Step-by-step explanation:

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3 years ago
Picture attached!! help!
o-na [289]
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3 0
3 years ago
Richard walks every day for exercise at a rate of 1 kilometer every 20 minutes.
OleMash [197]

Answer:

3000 meters

Step-by-step explanation:

1 kilometer = 1000 meters

1 kilometers = every 20 minutes

3× 1000 meters= 20 min ×3

3000 meters = 60 min/ 1 hour

7 0
3 years ago
Which of the following estimates at a 95% confidence level most likely comes from a small sample
Nikitich [7]

Answer:

Answer is c

Step-by-step explanation:

In hypothesis testing whether to accept or reject null hypothesis, normally we find one method as using confidence interval.  If the test statistic lies within confidence interval, we accept otherwise we reject.

For arriving confidence intervals we add and subtract margin of error from the mean we use in null hypothesis.

Margin of error = std error * critical value of test (Z or t etc)

For the same std deviation, std error = std dev/sq rt of sample size

Thus std error is inversely proportional to the square root of sample size.

If n becomes larger, std error becomes smaller and vice versa.

So margin of error increases for smaller sample size.

Since we have to select confidence level from a small sample, we have to select one which has the greatest margin of error=18

Hence answer is

c)  71%(+/-18%)

5 0
3 years ago
Find the sum of the arithmetic sequence. 3,5,7,9,....,21
inysia [295]
The sum of any arithmetic sequence is the average of the first and last terms times the number of terms.

Any term in an arithmetic sequence is:

a(n)=a+d(n-1), where a=initial term, d=common difference, n=term number

So the first term is a, and the last term is a+d(n-1) so the sum can be expressed as:

s(n)(a+a+d(n-1))(n/2)

s(n)=(2a+dn-d)(n/2)

s(n)=(2an+dn^2-dn)/2

However we need to know how many terms are in the sequence.

a(n)=a+d(n-1), and we know a=3 and d=2 and a(n)=21 so

21=3+2(n-1)

18=2(n-1)

9=n-1

10=n so there are 10 terms in the sequence.

s(n)=(2an+dn^2-dn)/2, becomes, a=3, d=2, n=10

s(10)=(2*3*10+2*10^2-2*10)/2

s(10)=(60+200-20)/2

s(10)=240/2

s(10)=120
7 0
3 years ago
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