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3 years ago

What is Charles' law formula?

1 answer:

8 0

In the 1800s a French scientist named Jacques Charles made discoveries regarding the effect of temperature on gases. Charles law states that at a constant pressure the volume of a given mass of gas is directly proportional to the absolute temperature.

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Write the appropriate symbol for each of the following isotopes: (a) Z 11, A 23; (b) Z= 28, A= 64; (c) Z= 50, A =115; (d) Z= 20,

prohojiy [21]

Explanation:

Z = atomic mass of the element and , A = atomic mass of the element .

a) Z = 11, A = 23

Element = Sodium

symbol: ²³₁₁Na .

b) Z = 28, A = 64

Element = Nickel

symbol: ⁶⁴₂₈Ni .

c) Z = 50, A = 115

Element = tin

symbol: ¹¹⁵₅₀Sn .

d) Z = 20, A = 42

Element = Calcium

symbol: ⁴²₂₀Ca .

6 0

3 years ago

Read 2 more answers

Name the four elements on the Periodic Table that are considered METALLOIDS?

Nimfa-mama [501]

Answer:

boron (B), silicon (Si), germanium (Ge), arsenic (As), antimony (Sb), tellurium (Te), polonium (Po) and astatine (At)

Explanation:

metalloids are elements that are in between the metals and nonmetals. they are in between because they have properties of both metals and nonmetals.

you can search "metalloids on the periodic table" and go to images to see what i mean :)

5 0

3 years ago

A molecule consisting of more than one element that are chemically combined.

BaLLatris [955]

Answer:

compound, but I could be wrong

4 0

2 years ago

Use the data given below to construct a Born-Haber cycle to determine the second ionization energy of Ca. Δ H°(kJ) Ca(s)→Ca(g) 1

Drupady [299]

Answer : The value of second ionization energy of Ca is 1010 kJ.

Explanation :

The formation of calcium oxide is,

$Ca(s)+\frac{1}{2}O_2(g)\overset{\Delta H_f}\rightarrow CaO(s)$

$\Delta H_f^o$ = enthalpy of formation of calcium oxide = -635 kJ

The steps involved in the born-Haber cycle for the formation of $CaO$ :

(1) Conversion of solid calcium into gaseous calcium atoms.

$Ca(s)\overset{\Delta H_s}\rightarrow Ca(g)$

$\Delta H_s$ = sublimation energy of calcium = 193 kJ

(2) Conversion of gaseous calcium atoms into gaseous calcium ions.

$Ca(g)\overset{\Delta H_I_1}\rightarrow Ca^{+1}(g)$

$\Delta H_I_1$ = first ionization energy of calcium = 590 kJ

(3) Conversion of gaseous calcium ion into gaseous calcium ions.

$Ca^{+1}(g)\overset{\Delta H_I_2}\rightarrow Ca^{+2}(g)$

$\Delta H_I_2$ = second ionization energy of calcium = ?

(4) Conversion of molecular gaseous oxygen into gaseous oxygen atoms.

$O_2(g)\overset{\Delta H_D}\rightarrow OI(g)$

$\frac{1}{2}O_2(g)\overset{\Delta H_D}\rightarrow O(g)$

$\Delta H_D$ = dissociation energy of oxygen = $\frac{498}{2}=249kJ$

(5) Conversion of gaseous oxygen atoms into gaseous oxygen ions.

$O(g)\overset{\Delta H_E_1}\rightarrow O^-(g)$

$\Delta H_E_1$ = first electron affinity energy of oxygen = -141 kJ

(6) Conversion of gaseous oxygen ion into gaseous oxygen ions.

$O^-(g)\overset{\Delta H_E_2}\rightarrow O^{2-}(g)$

$\Delta H_E_2$ = second electron affinity energy of oxygen = 878 kJ

(7) Conversion of gaseous cations and gaseous anion into solid calcium oxide.

$Ca^{2+}(g)+O^{2-}(g)\overset{\Delta H_L}\rightarrow CaO(s)$

$\Delta H_L$ = lattice energy of calcium oxide = -3414 kJ

To calculate the overall energy from the born-Haber cycle, the equation used will be:

$\Delta H_f^o=\Delta H_s+\Delta H_I_1+\Delta H_I_2+\Delta H_D+\Delta H_E_1+\Delta H_E_2+\Delta H_L$

Now put all the given values in this equation, we get:

$-635kJ=193kJ+590kJ+\Delta H_I_2+249kJ+(-141kJ)+878kJ+(-3414kJ)$

$\Delta H_I_2=1010kJ$

Therefore, the value of second ionization energy of Ca is 1010 kJ.

6 0

2 years ago

E.) MO(NO2)3<br> What’s the name

astraxan [27]

Answer:

Molybdenum Nitrite

Explanation:

Mo => Molybdenum

NO2 => Nitrite

4 0

3 years ago