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Aleks [24]
3 years ago
15

What is the term for a process by which molecules of a solvent tend to pass through a semipermeable membrane from a less concent

rated solution into a more concentrated one, thus equalizing the concentrations on each side of the membrane?
1. Osmosis
2. Diffusion
3. Dialysis
4. Filteration
Chemistry
1 answer:
Lubov Fominskaja [6]3 years ago
5 0
The answer is:
Osmosis
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15 POINTS PLEASE HELP What volume of water must be added to 35mL of 2.6m KCl to reduce its concentration to 1.2m? Please explain
BartSMP [9]
First, find the volume the solution needs to be diluted to in order to have the desired molarity:
You have to use the equation M₁V₁=M₂V₂ when ever dealing with dilutions.

M₁=the starting concentration of the solution (in this case 2.6M)
V₁=the starting volume of the solution (in this case 0.035L)
M₂=the concentration we want to dilute to (in this case 1.2M)
V₂=the volume of solution needed for the dilution (not given)

Explaining the reasoning behind the above equation:
MV=moles of solute (in this case KCl) because molarity is the moles of solute per Liter of solution so by multiplying the molarity by the volume you are left with the moles of solute.  The moles of solute is a constant since by adding solvent (in this case water) the amount of solute does not change.  That means that M₁V₁=moles of solute=M₂V₂ and that relationship will always be true in any dilution.

Solving for the above equation:
V₂=M₁V₁/M₂
V₂=(2.6M×0.035L)/1.2M
V₂=0.0758 L
That means that the solution needs to be diluted to 75.8mL to have a final concentration of 1.2M.

 Second, Finding the amount of water needed to be added:
Since we know that the volume of the solution was originally 35mL and needed to be diluted to 75.8mL to reach the desired molarity, to find the amount of solvent needed to be added all you do is V₂-V₁ since the difference in the starting volume and final volume is equal to the volume of solvent added.
75.8mL-35mL=40.8mL
40.8mL of water needs to be added

I hope this helps.  Let me know if anything is unclear.
Good luck on your quiz!
5 0
4 years ago
A car mechanic had a sealed bucket containing a substance in the gas phase. She left the bucket outside over the weekend. When s
motikmotik
A phase change from Gas to liquid means that it was cold outside and so the molecules went from being very free moving to forming bonds with one another due to the cold.
4 0
3 years ago
3 complete paragraphs on Static Electricity
Digiron [165]

Answer: Employments of friction based electricity incorporate contamination control, Xerox machines, and painting. They utilize the property that inverse electrical charges pull in. There are different utilizations including the properties of aversion and the making of electricity produced via friction flashes

friction based electricity is an awkwardness of electric charges inside or on the outside of a material. The charge stays until it can move away through an electric flow or electrical release.

In view of similar kinds of examinations like the one you performed, researchers had the option to set up three laws of electrical charges: Inverse charges pull in one another. Like charges repulse one another. Charged items pull in nonpartisan articles.

4 0
3 years ago
What is unique about the moons that orbit Jupiter? (select all that apply)
Zepler [3.9K]

Answer:

Some of the orbits are nearly circular, while the moons farthest from Jupiter have more irregular orbits. The outer moon's orbit in the opposite direction in which Jupiter spins, which is unusual and indicates the moons were asteroids that were sucked into Jupiter's orbit after the initial system was formed.

Explanation:

8 0
3 years ago
Read 2 more answers
A certain liquid X has a normal freezing point of 7.60 °C and a freezing point depression constant K= 6.90 °C-kg-mol. Calculate
Dmitry [639]

<u>Answer:</u> The freezing point of solution is -5.11°C

<u>Explanation:</u>

Vant hoff factor for ionic solute is the number of ions that are present in a solution. The equation for the ionization of sodium chloride follows:

NaCl(aq.)\rightarrow Na^{+}(aq.)+Cl^-(aq.)

The total number of ions present in the solution are 2.

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute (NaCl) = 7.57 g

M_{solute} = Molar mass of solute (NaCl) = 58.44 g/mol

W_{solvent} = Mass of solvent (liquid X) = 350.0 g

Putting values in above equation, we get:

\text{Molality of }NaCl=\frac{7.57\times 1000}{58.44\times 350.0}\\\\\text{Molality of }NaCl=0.370m

To calculate the depression in freezing point, we use the equation:

\Delta T=iK_fm

where,

i = Vant hoff factor = 2

K_f = molal freezing point depression constant = 6.90°C/m

m = molality of solution = 0.370 m

Putting values in above equation, we get:

\Delta T=2\times 6.90^oC/m.g\times 0.370m\\\\\Delta T=5.11^oC

Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.

\Delta T=\text{freezing point of water}-\text{freezing point of solution}

\Delta T = 5.11 °C

Freezing point of water = 0°C

Freezing point of solution = ?

Putting values in above equation, we get:

5.106^oC=0^oC-\text{Freezing point of solution}\\\\\text{Freezing point of solution}=-5.11^oC

Hence, the freezing point of solution is -5.11°C

7 0
4 years ago
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