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Kamila [148]
3 years ago
6

What are the solutions of 4x2 - 8x +5 = 0 ?

Mathematics
2 answers:
Nataliya [291]3 years ago
7 0

Answer: option C is the correct answer

Step-by-step explanation:

The given quadratic equation is expressed as

4x² - 8x + 5 = 0

The equation is already in the standard form of ax² + bx + c

The general formula for solving quadratic equations is expressed as

x = [- b ± √(b² - 4ac)]/2a

From the equation given,

a = 4

b = - 8

c = 5

Therefore,

x = [- - 8 ± √(- 8² - 4 × 4 × 5)]/2 × 4

x = [8 ± √(64 - 80)]/8

x = [8 ± √- 16]/8

x = (8 + 4i)/8 or x = (8 - 4i)/8

x = (2 + i)/2 or x = (2 - i)/2

MrRissso [65]3 years ago
6 0

Answer:

x= {2+ i}/2 , {2- i}/2 = C

Step-by-step explanation:

4x² - 8x +5 = 0

using quadratic formula

x= {-b±√b²-4ac}/2a

x= [-(-8)±√(-8)²-4(4)(5)] /2x4 = [8±√64-80]/8= [8±√-16]/8 = {8±4 i}/8

x= {8+4 i}/8 , {8-4 i}/8

x=4 {2+ i}/8 , {2- i}/8

4 divides 8

x= {2+ i}/2 , {2- i}/2 = c

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erma4kov [3.2K]
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7 0
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Find the values of x and y
zhuklara [117]

You can use a tangent:

tangent=\dfrac{opposite}{adjacent}

We have opposite = 17 and adjacent = x.

\tan30^o=\dfrac{\sqrt3}{3}

substitute:

\dfrac{17}{x}=\dfrac{\sqrt3}{3}       cross multiply

x\sqrt3=(3)(17)     multiply both sides by √3

x(\sqrt3)(\sqrt3)=51\sqrt3

3x=51\sqrt3      divide both sides by 3

x=17\sqrt3

Use the Pythagorean theorem:

y^2=(17\sqrt3)^2+17^2\\\\y^2=289(\sqrt3)^2+289\\\\y^2=289\cdot3+289\\\\y^2=867+289\\\\y^2=1156\to y=\sqrt{1156}\\\\y=34

-------------------------------------------------------------------------------------------------

Other method.

30^o-60^o-90^o triangle.

The sides are in the ratio 1:2:\sqrt3\to17:y:x

Therefore

17:(2\cdot17):(17\sqrt3)\to17:34:17\sqrt3\to x=34,\ y=17\sqrt3

 


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Which Number has the highest value?<br><br> -25<br><br> 16<br><br> -32<br><br> 34
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Answer:

34

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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