The tendency of a material to oppose the flow of charge is called: B) resistance
Answer
given,
Distance for decibel reading
r₁ = 13 m
r₂ = 24 m
When the engineer is at r₁ reading is β₁ = 101 dB
now, Calculating the Intensity at r₁
Using formula
I₀ = 10⁻¹² W/m²
now inserting the given values
I = 0.01258 W/m²
now, calculating power at r₁
P₁ = I₁ A₁
P₁ = 0.01258 x 4 π r²
P₁ = 0.01258 x 4 π x 13²
P₁ = 26.72 W
Answer:
V = 308.1 m/s θ = -64º
Explanation:
a and b) We will use the projectile launch equations where we are asked to find the speed when the tank reaches the ground
Let's start by breaking down the speed
Vox = Vo cos θ
Voy = Vo sint θ
Vox = 140 cos 15 = 135.2 m / s
Voy = 140 sin 15 = 36.2 m / s
Let's look for vertical speed when it hits the ground
Vy² = Voy² - 2gy
Vy = √(36.2² - 2 9.8 3.98 103) = √ (1310-78008)
Vy = 276.9 m / s
We have both components.
V² = Vx² + Vy²
V = √ (135.2² + 276.9²)
V = 308.1 m / s
tan θ = Vy / Vx
tan θ = -276.9 / 135.2 = 2,048
θ = -64º
The negative sign means that it is measured from the x-axis clockwise
c and d) We repeat the same calculation for tank B, the only difference is the angle T = -15º
Vox = 140 cos (-15)
Voy = 140 sin (-15)
Vox = 135.2 m / s
Voy = 140 sin (-15)
Voy = -36.2 m / s
We calculate the vertical speed
Vy² = Voy² - 2 g Y
Vy = √ ((-36.2)² - 2 9.8 3980)
Vy = 276.9 m / s
V = √(135.3²2 + 276.9²)
V = 308.1 m/s
tan θ = -276.9 / 135.2
θ = -64
You can see that the speeds and angles are the same in both cases, the difference between these two situations is in the horizontal distance that runs each story
To solve this problem we will apply the physical equations of the angular kinematic movement, for which it defines the square of the final angular velocity as the sum between the square of the initial angular velocity and the product between 2 times the angular acceleration and angular displacement. We will clear said angular displacement to find the correct response
Using,
Here,
= Final angular velocity
= Initial angular velocity
Angular acceleration
Angular displacement
Replacing,
Therefore the correct answer is C.