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3 years ago

15

Pelican hunts fish in the water as th pelican the waters surface why must it aim for the fish in a slightly different place than

where the fish appears to be located

1 answer:

Karo-lina-s [1.5K]3 years ago

6 0

Answer:

because the light bounces off of the water creating a bend. the answer is d.

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Which of the following statements about the rings of the four jovian planets is not true? a. All rings lie within their planet's

nadya68 [22]

C. all have gaps and ringlets.

5 0

4 years ago

A wheel of mass 60.0 kg is pushed with a net force of 26.4 N. Find acceleration.

worty [1.4K]

F= ma; a= F/m

a = 26.4 N/60 kg= 0.44 m/s^2

4 0

3 years ago

In our new car we will be able to drive 30 miles in a half an hour from this information we can determine the cars acceleration

Vika [28.1K]

Answer:

By the information provided we can find the cars speed.

Explanation:

Speed is the distance traveled by any object in certain time. As we have distance traveled by car as 30 miles.
And time taken by car to travel 30 miles is half an hour. So speed is easily calculated as, $Speed = \frac{Distance }{Time }$ .
Velocity is a vector quantity so we cannot determine velocity by knowing only distance and time, we need additional information of direction to know cars velocity.
So the speed will be, $Speed =$ $\frac{30}{0.5} = 60 miles/hour$ .

6 0

3 years ago

An overnight rainstorm has caused a major roadblock. Three massive rocks of mass m1=584 kg, m2=838 kg, and m3=322 kg have blocke

Elena-2011 [213]

Answer:

Force must be applied to m₁ to move the group of rocks from the road at 0.250 m/s² = 436 N

Explanation:

Total force required = Mass x Acceleration,

F = ma

Here we need to consider the system as combine, total mass need to be considered.

Total mass, a = m₁+m₂+m₃ = 584 + 838 + 322 = 1744 kg

We need to accelerate the group of rocks from the road at 0.250 m/s²

That is acceleration, a = 0.250 m/s²

Force required, F = ma = 1744 x 0.25 = 436 N

Force must be applied to m₁ to move the group of rocks from the road at 0.250 m/s² = 436 N

8 0

3 years ago

A policeman investigating an accident measures the skid marks left by a car on the horizontal road. He determines that the dista

sleet_krkn [62]

<h2>The velocity of car was m m/s </h2>

Explanation:

When the car skids , its centripetal force is provided by frictional force .

Here centripetal force F = $\frac{mv^2}{r}$

here v is the velocity of car and r is the radius of the curve .

The frictional force f = μ R

here μ is the coefficient of kinetic friction and R is normal reaction

Thus f = m g

On horizontal road R = mg

Thus F = f at the time of skid .

Thus v = $\sqrt{\mu rg}$

= $\sqrt{0.29x23.74x10}$ = 9 m/s

3 0

3 years ago