Question

→Fo

Answer 1

The weight of the block is ( Fo g ) / ( g + 3 a )

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Further explanation

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

$\large {\boxed {F = ma }$

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

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Given:

mass of block = M

acceleration of block = 3a

constant force = Fo

Asked:

weight of block = w = ?

Solution:

We will use Second Law of Newton as follows:

$\Sigma F = ma$

$Fo - Mg = M(3a)$

$Fo = Mg + 3Ma$

$Fo = M(g + 3a)$

$M = Fo \div ( g + 3a )$

$\large{ \boxed{M = \frac{Fo}{g + 3a}}}$

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$w = Mg$

$w = \frac{Fo}{g + 3a} \times g$

$\large {\boxed {w = Fo \times \frac{g}{g + 3a}}}$

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Learn more

• Impacts of Gravity : brainly.com/question/5330244
• Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
• The Acceleration Due To Gravity : brainly.com/question/4189441
• Newton's Law of Motion: brainly.com/question/10431582
• Example of Newton's Law: brainly.com/question/498822

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Answer details

Grade: High School

Subject: Physics

Chapter: Dynamics

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Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant

Answer 2

Answer:

The mass of the block, M =T/(3a +g)  Kg

Explanation:

Given,

The upward acceleration of the block a = 3a

The constant force acting on the block, F₀ = Ma = 3Ma

The mass of the block, M = ?

In an Atwood's machine, the upward force of the block is given by the relation

                                     Ma = T - Mg

                                      M x 3a = T - Ma    

                                    3Ma + Mg = T

                                       M = T/(3a +g)  Kg

Where 'T' is the tension of the string.

Hence, the mass of the block in Atwood's machine is, M = T/(3a +g)  Kg