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maxonik [38]
3 years ago
13

→Fo

Physics
2 answers:
Sindrei [870]3 years ago
5 0

The weight of the block is ( Fo g ) / ( g + 3 a )

\texttt{ }

<h3>Further explanation</h3>

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

\large {\boxed {F = ma }

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

\texttt{ }

<u>Given:</u>

mass of block = M

acceleration of block = 3a

constant force = Fo

<u>Asked:</u>

weight of block = w = ?

<u>Solution:</u>

We will use Second Law of Newton as follows:

\Sigma F = ma

Fo - Mg = M(3a)

Fo = Mg + 3Ma

Fo = M(g + 3a)

M = Fo \div ( g + 3a )

\large{ \boxed{M = \frac{Fo}{g + 3a}}}

\texttt{ }

w = Mg

w = \frac{Fo}{g + 3a} \times g

\large {\boxed {w = Fo \times \frac{g}{g + 3a}}}

\texttt{ }

<h3>Learn more</h3>
  • Impacts of Gravity : brainly.com/question/5330244
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
  • The Acceleration Due To Gravity : brainly.com/question/4189441
  • Newton's Law of Motion: brainly.com/question/10431582
  • Example of Newton's Law: brainly.com/question/498822

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Dynamics

\texttt{ }

Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant

irakobra [83]3 years ago
3 0

Answer:

The mass of the block, M =T/(3a +g)  Kg

Explanation:

Given,

The upward acceleration of the block a = 3a

The constant force acting on the block, F₀ = Ma = 3Ma

The mass of the block, M = ?

In an Atwood's machine, the upward force of the block is given by the relation

                                     Ma = T - Mg

                                      M x 3a = T - Ma    

                                    3Ma + Mg = T

                                       M = T/(3a +g)  Kg

Where 'T' is the tension of the string.

Hence, the mass of the block in Atwood's machine is, M = T/(3a +g)  Kg

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