If the basketball hoop is 10 ft high and located 15 ft away, what initial velocity v should the basketball have?

each of equal sides of an isosceles triangle is 4cm greater than its height .If the base of triangle is 24 cm ,calculate the per

Montano1993 [528]

<h3>Answer:-</h3>

192 cm²

<h3>Step by step explanation :-</h3>

Let us take the height be x , then its side = x + 4. Now half of base will be 12 cm .

According to Pythagoras Theorem :-

=> base² + perpendicular ² = hypontenuse ²

=> 12² + x² = (x+4)²

=> 144 + x² = x² + 16 + 8x

=> 8x = 144-16

=> 8x = 128

=> x = 128/8

=> x = 16 cm .

Hence the height of ∆ is 16 cm .So the area will be half the product of base and altitude.

= 1/2 * 16 cm * 24cm .

= 192 cm²

<h3>★ Hence the area of the triangle is 192 cm² .</h3>

8 0

2 years ago

Please help someone pleaseeeeeeeeeeeeeeeeeeee

Ray Of Light [21]

Mean is adding all the numbers then dividing the answer you go from the numbers.

7 0

3 years ago

Read 2 more answers

john has $305, and he is spending $3 each day. which algebraic expression describes this situation, where d represents the numbe

Artist 52 [7]

The answer whould be like this

305 - 3d

8 0

3 years ago

PLEASE HELP ME GUYS OR I WONT PASS this calculus!!!!

KonstantinChe [14]

Answer:

b. $\displaystyle \frac{1}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Functions
Function Notation
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle H(x) = \sqrt[3]{F(x)}$

Step 2: Differentiate

Rewrite function [Exponential Rule - Root Rewrite]: $\displaystyle H(x) = [F(x)]^\bigg{\frac{1}{3}}$
Chain Rule: $\displaystyle H'(x) = \frac{d}{dx} \bigg[ [F(x)]^\bigg{\frac{1}{3}} \bigg] \cdot \frac{d}{dx}[F(x)]$
Basic Power Rule: $\displaystyle H'(x) = \frac{1}{3}[F(x)]^\bigg{\frac{1}{3} - 1} \cdot F'(x)$
Simplify: $\displaystyle H'(x) = \frac{F'(x)}{3}[F(x)]^\bigg{\frac{-2}{3}}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle H'(x) = \frac{F'(x)}{3[F(x)]^\bigg{\frac{2}{3}}}$

Step 3: Evaluate

Substitute in x [Derivative]: $\displaystyle H'(5) = \frac{F'(5)}{3[F(5)]^\bigg{\frac{2}{3}}}$
Substitute in function values: $\displaystyle H'(5) = \frac{6}{3(8)^\bigg{\frac{2}{3}}}$
Exponents: $\displaystyle H'(5) = \frac{6}{3(4)}$
Multiply: $\displaystyle H'(5) = \frac{6}{12}$
Simplify: $\displaystyle H'(5) = \frac{1}{2}$