Answer:
Part 11) 
, 
Part 2) 4+3i
Step-by-step explanation:
Part 11) write a recursive rule for the sequence
Let
we know that
----> 
----> 
----> 
This is an arithmetic sequence
In an Arithmetic Sequence the difference between one term and the next is a constant, and this constant is called the common difference (d).
In this problem the common difference is equal to 
therefore
A recursive rule for the sequence is
substitute the value of d
where
Part 12) What is the complex conjugate of 4-3i?
we know that
The <u><em>complex conjugate</em></u> of a complex number is the number with an equal real part and an imaginary part equal in magnitude but opposite in sign
so
we have that
the real part of the given number is 4 and the the imaginary part is -3i
so
the imaginary part equal in magnitude but opposite in sign is +3i
therefore
the complex conjugate of the given number is equal to
Area = length x width
So, 36/3 = 12
Width is 12
Answer:
196 ft
Step-by-step explanation:
Bc im guessing
Mark as smartest and Brainliest
To answer, first, convert the given velocity in km/h to m/s as shown below,
(144 km / hr) x (1000 m / 1 km) x (1 hr / 3600 s) = 40 m/s
The acceleration (a) is solved by through the equation,
a = (Vf - Vi) / Δt
where Vf and Vi are final and initial velocities, respectively and Δt is change in time. Substituting the known values,
a = (0 - 40 m/s) / 12 s = -3.3 m/s²
Thus, the answer to this item is letter B.
Answer:
A). A(t) = P(1+r/n)^(nt)
B). DA/Dt = np(1+r/n)^(t)
C). A(5) =$ 5664.0
D).t = approximately 13.5 years
Step-by-step explanation:
A(t) = P(1+r/n)^(nt)
P = $5000
n= t
r= 2.5%
After five years t = 5
A(t) = P(1+r/n)^(nt)
A(5) = 5000(1+0.025/5)^(5*5)
A(5) = 5000(1+0.005)^(25)
A(5)= 5000(1.005)^(25)
A(5) = 5000(1.132795575)
A(5) = 5663.977875
A(5) =$ 5664.0
When the balance A= $7000
A(t) = P(1+r/n)^(nt)
7000= 5000(1+0.025/n)^(nt)
But n= t
7000= 5000(1+0.025/t)^(t²)
7000/5000= (1+0.025/t)^(t²)
1.4= (1+0.025/t)^(t²)
Using trial and error
t = approximately 13.5 years
