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seraphim [82]
2 years ago
5

The marginal cost function for a company is given by

Mathematics
1 answer:
nikklg [1K]2 years ago
6 0

Answer:

1503.37

Step-by-step explanation:

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I need to find the area of the shaded region
spin [16.1K]
Well first find the area of the semi-circle. 

If the area of a cricle is equal to pi*radius^2 , then you can just find that and divide by 2.

So, A = pi*2^2. = 4pi

We know that the radius is 2 because the length of the side of the rectangle is 4, meaning that the diameter of the semi-circle is 4, and so the radius is 2 as it is half of the diameter. 

We can easily calculate the area of the rectangle, which is
 Length * width = 6*4 = 24.

Next we divide 4pi by 2 in order to get the area of the semi-circle, giving us an area of 2pi

We can just subtract 2pi from 24 and get the area of the shaded region.

Area of the shaded region (answer): 17.7
4 0
3 years ago
Please help with this fast
vitfil [10]

Answer:

repost it, I cant see all of the question

3 0
3 years ago
A spool contains 270 inches of wire. How many pieces of wire, each with the a length of 1 7/8 inches, can be cut from the spool?
prisoha [69]
You would be able to cut 144 pieces of wire from the spool because 270/1 7/8 (or 1.875) equals 144
6 0
2 years ago
At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?
hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

d*sin(\theta) = m\lambda

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle              

At the first-order maximum (m=1) at 20.0 degrees we have:

\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342

Now, to produce a second-order maximum (m=2) the angle must be:

sin(\theta) = \frac{\lambda}{d}*m

\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.    

I hope it helps you!                                                        

6 0
3 years ago
I mark brainliest for all my questions that are answered right :) thx for helping me
allsm [11]
The correct answer is y= 0.513(1.833)^x


Explain


We will use the equation on this form

Y=ab^x

Let’s us plug in the coordinates of first point

(X, y) , ( 9, 120)

We will have

Y=ab^x

120= ab^9

Our equation for a will be

Ab^9 = 120

ab ^9 / b^9 = 120/ b^9


a = 120/ b^9

So will have


Y= 120/ b^9 • b^x

Then we will plug in coordinates for the second point


( x,y) = ( 10, 220)

We will have

Y= 120/b^9 • b^x

220 = 120/b^9 • b^10-9


220= 120b

Divide both side by 120

B= 11/6

B= 1.833333 = 1.833



Let’s plug in the value b=11/6 to our equation for a


A= 120/b^9

A= 120/ 11/6^9

A= 120/11^9/6^9


A=120 • 6^9 / 11^9

= 0.51285 which equal to 0.513



So therefore the answer is

Y= 0.513(1.833)^x


I hope this help you

:D
8 0
3 years ago
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