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Shalnov [3]
3 years ago
6

When would u need an interpreter? What would that person do?

Mathematics
2 answers:
seropon [69]3 years ago
6 0
If you speak a different language this person can interpret your speaking into the language understandable by the other party
ale4655 [162]3 years ago
3 0
You would need an interpreter when you are trying to converse with someone who speaks another language that you dont know. the interpreter would translate the language you dont know so you can converse
You might be interested in
Let f(x)= x^2-4x-c. Find a nonzero value of c such that f(c)=c.​
Dimas [21]

Answer:

The nonzero value of c will be:

  • c = 6

Step-by-step explanation:

Given the function

f\left(x\right)=\:x^2-4x-c

f\left(c\right)=\:c^2-4c-c

as

f(c) = c

so

c=\:c^2-4c-c

switching the sides

c^2-4c-c=c

subtract c from both sides

c^2-4c-c-c=c-c

c^2-6c=0

c\left(c-6\right)=0

Using the zero factor principle

\:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

c=0\quad \mathrm{or}\quad \:c-6=0

so, the solutions to the quadratic equations are:

c=0,\:c=6

Therefore, a nonzero value of c will be:

  • c = 6
5 0
3 years ago
Pleas someone help me with this it's my last question
ruslelena [56]

Answer:

we need to find out if the following get x = 2 as a final product

-2(x-4) = 4

-2x + 8 = 4

-2x = -4

x = 2

so it is a solution

26/x = 13

26 = 13x

x = 26/13

x = 2

so it’s a solution

-3.8x = -7.4

x = 7.4/3.8 ≠ 2

you get ≈ 1.95

so it’s not a solution

4(x-1) - 3(x-2) = -8

4x - 4 - 3x + 6 = -8

x + 2 = -8

x = -10

so it’s not a solution

5 0
2 years ago
Read 2 more answers
Select the correct answer.
Elena L [17]

Answer:

b because first u need to remove the parentheses then u disturbe

8 0
3 years ago
Which value is equivalent to 7 multiplied by 3 multiplied by 2 whole over 7 multiplied by 5, the whole raised to the power of 2
PilotLPTM [1.2K]

Answer:

36/25

Step-by-step explanation:

7 multiplied by 3 multiplied by 2 whole over 7 multiplied by 5, the whole raised to the power of 2 multiplied by 7 to the power of 0 over 5 to the power of negative 3, whole to the power of 3 multiplied by 5 to the power of negative 9

((7 * 3 * 2)/(7 * 5))^2 * (7^0/5^-3)^3 * 5^-9 =

= (42/35)^2 * (1 * 5^3)^3 * 5^-9

= (6/5)^2 * 5^9* 5^-9

= 36/25 * 5^0

= 36/25

8 0
2 years ago
The cost of John’s bike(p) cannot exceed $5,000. Write this sentence in the form of a set notation.
lakkis [162]

Answer:

p = \{x \ |  \ x \in Q^+ \  and \ x \leq \$5,000 \}

Step-by-step explanation:

The expression for the cost of John's bike (p) using set notation can written as follows;

We note that the cost of the bike is a member of the positive rational number  and the cost price of the bike cannot exceed $5,000, therefore, it is less than or equal to $5,000, therefore, we get the following set notation;

p = \{x \ |  \ x \in Q^+ \  and \ x \leq \$5,000 \}

5 0
3 years ago
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