<h3>
Answer: Choice A</h3>
- Domain: x > 4
- Range: y > 0
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Explanation:
We want to avoid having a negative number under the square root. Solving
leads to 
So it appears the domain could involve x = 4 itself; however, if we tried that x value, then we'd get a division by zero error.
So in reality, the domain is x > 4.
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The range of y = sqrt(x) is the set of positive real numbers. So y > 0 is the range for this equation. Shifting left and right does not affect the range, so the range of y = sqrt(x-4) is also y > 0.
We are dividing a positive number (3) over some positive number in the denominator. Overall, the expression
is positive because positive/positive = positive.
Therefore, the range of the given equation is y > 0
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The graph is shown below. We have a vertical asymptote at x = 4 and a horizontal asymptote at y = 0. The green curve is fenced in the upper right corner (northeast corner).
Answer:
The answer would be 7 I hope this helps! : )
Answer:
the first answer y=-8/5x+19.4
Step-by-step explanation:
Please tell me if the answer is right and if it is right click on thanks i appreciate it
Answer:
48x² + 24x + 3
Step-by-step explanation:
Width = (4x + 1) in
Length = 3 *width = 3*(4x + 1) = 3*4x + 3*1
= (12x + 3) in
Area of rectangle = length * width
= (12x + 3) (4x + 1)
= 12x *4x + 12x *1 + 3*4x + 3*1
= 48x² + 12x + 12x + 3
= 48x² + 24x + 3
So
x=hours
y=pay
use a piecewise function maybe
for x≤40, use y=21x
for x>40, use 840+1.5(21(x-40))
k, sso 46>40 so
840+1.5(21(46-40))
840+1.5(21(6))
840+1.5(126)
840+189
1029
A. 840+1.5(21(x-40))
B. $1029