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sashaice [31]
3 years ago
15

Tina placed a 15 meter rope along one side of the bicycle path. She hung a ribbon on each end of the rope and every 3 meters in-

between. How many ribbons did she hang?
Mathematics
1 answer:
dusya [7]3 years ago
7 0
Hello!

She placed 6 ribbons

2 at the ends and 5 every 3 meters
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Please help find domain and range
Oxana [17]
<h3>Answer:  Choice A</h3>
  • Domain:  x > 4
  • Range: y > 0

========================================================

Explanation:

We want to avoid having a negative number under the square root. Solving x-4 \ge 0 leads to x \ge 4

So it appears the domain could involve x = 4 itself; however, if we tried that x value, then we'd get a division by zero error.

So in reality, the domain is x > 4.

-------------

The range of y = sqrt(x) is the set of positive real numbers. So y > 0 is the range for this equation. Shifting left and right does not affect the range, so the range of y = sqrt(x-4) is also y > 0.

We are dividing a positive number (3) over some positive number in the denominator. Overall, the expression \frac{3}{\sqrt{x-4}} is positive because positive/positive = positive.

Therefore, the range of the given equation is y > 0

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The graph is shown below. We have a vertical asymptote at x = 4 and a horizontal asymptote at y = 0. The green curve is fenced in the upper right corner (northeast corner).

3 0
3 years ago
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skad [1K]

Answer:

The answer would be 7 I hope this helps! : )

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Which equation represents a nonlinear function
Inga [223]

Answer:

the first answer y=-8/5x+19.4

Step-by-step explanation:

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3 years ago
WILL GIVE BRAINLIEST!
siniylev [52]

Answer:

48x² + 24x + 3

Step-by-step explanation:

Width = (4x + 1) in

Length = 3 *width = 3*(4x + 1) = 3*4x + 3*1

           = (12x + 3) in

Area of rectangle = length * width

                             = (12x + 3) (4x + 1)

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                             = 48x² + 12x + 12x + 3

                              = 48x² + 24x + 3

8 0
3 years ago
When working overtime, an auto mechanic gets paid 1.5 times the normal hourly wage. Overtime is the amount of time worked beyond
DedPeter [7]
So

x=hours
y=pay

use a piecewise function maybe

for x≤40, use y=21x


for x>40, use 840+1.5(21(x-40))


k, sso 46>40 so

840+1.5(21(46-40))
840+1.5(21(6))
840+1.5(126)
840+189
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A. 840+1.5(21(x-40))
B. $1029
7 0
3 years ago
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