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sashaice [31]
3 years ago
15

Tina placed a 15 meter rope along one side of the bicycle path. She hung a ribbon on each end of the rope and every 3 meters in-

between. How many ribbons did she hang?
Mathematics
1 answer:
dusya [7]3 years ago
7 0
Hello!

She placed 6 ribbons

2 at the ends and 5 every 3 meters
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Solve. High school pre-cal
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Answer:

<em>Answer: Quadrant 4</em>

Step-by-step explanation:

<u>Graph of Functions </u>

Let's analyze the function  

\displaystyle y=\frac{x^2+3x}{x+1}

To better understand the following analysis, we'll factor y

\displaystyle y=\frac{x(x+3)}{x+1}

For y to have points in the first quadrant, at least one positive value of x must produce one positive value of y. It's evident that any x greater than 0 will do. For example, x=1 will make y to be positive in the numerator and in the denominator, so it's positive

For y to have points in the second quadrant, at least one negative value of x must produce one positive value of y. We need two of the factors that are negative. It can be seen that x=-2 will make y as positive, going through the second quadrant.

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How many significant digits are in 1000.10?<br> c. 5<br> b. 3<br> d. 6<br> a. 2
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What is the arc measure, in degrees, of major arc \stackrel{\large{\frown}}{ADC} ADC ⌢ A, D, C, start superscript, \frown, end s
Mrrafil [7]

Answer:

\stackrel{\large{\frown}}{ADC}    = 186^{\circ}

Step-by-step explanation:

Given

See attachment

Required

Determine the measure of \stackrel{\large{\frown}}{ADC}

The\ sum\ of\ angles\ in\ a\ circle\ is 360^{\circ}.

So, we have:

\stackrel{\large{\frown}}{ADC} + \stackrel{\large{\frown}}{APB}  + \stackrel{\large{\frown}}{BPC}  = 360^{\circ}

Where:

\stackrel{\large{\frown}}{APB}  = 70^{\circ}

\stackrel{\large{\frown}}{BPC}  = 104^{\circ}

Substitute these values in the above equation.

\stackrel{\large{\frown}}{ADC} + 70^{\circ}   +104^{\circ}   = 360^{\circ}

\stackrel{\large{\frown}}{ADC} + 174^{\circ}   = 360^{\circ}

Collect Like Terms:

\stackrel{\large{\frown}}{ADC}    = 360^{\circ} - 174^{\circ}

\stackrel{\large{\frown}}{ADC}    = 186^{\circ}

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Step-by-step explanation:


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