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Vladimir [108]
3 years ago
7

A charged particle (mass = M, charge = Q > 0) moves in a region of space where the magnetic field has a constant magnitude of

B and a downward direction. What is the magnetic force on the particle at an instant when it is moving horizontally toward the north with speed V?

Physics
1 answer:
oksian1 [2.3K]3 years ago
5 0

Answer:

Explanation:

the solution is found below

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Help??? Phases of the moon. Am I right
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The engine that moves the cables for the San Francisco cable cars delivers 390.3 kW of power for each line. How long does it tak
Musya8 [376]

Answer:

It would take 16.7 s for the work to be done by the engine.

Explanation:

From the question, given: Power = 390.3 kW

                                           Work to be done = 6.5 x 10^{6} J

But, power and work done with respect to time, has a relationship of:

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So that,

time = \frac{work done}{Power}

Thus,

time  = \frac{6.5*10^{6} }{390.3*10^{3} }

       = 16.6539

time = 16.7 s

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Thus, it would take 16.7 s for the work to be done by the engine.

5 0
3 years ago
Hey guys, is this question for a series circuit or for parallel?
Mandarinka [93]

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3 years ago
How far apart must two protons be if the electrical force acting on either one is equal to its weight on the earth's surface whe
BARSIC [14]

Answer:

G M m / R^2 = F   force of attraction for proton

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G M m / R^2 = K e^2 / r^2

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r^2 = 9E9 * (1.6E-19)^2 * (6.37E6)^2 / (6.67E-11 * 5.98E24 * 1.7E-27)

r^2 = 9 * 2.56 * 40.6 / (6.67 * 5.98 * 1.7) * 10^-19

r^2 = 1.38 * 10^-30

r = 1.17E-15 m

7 0
3 years ago
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