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dezoksy [38]
4 years ago
8

During a baseball game a pitcher threw a baseball, and the catcher, who was behind home plate, caught it. Which is true about th

e pitcher when the catcher caught the ball?
A) He saw the catcher catch the ball first.
B) He heard and saw the ball at the same time.
C) He heard the sound of the catcher's mitt first.
D) He saw the catcher catch the ball, but did not hear it.
Physics
2 answers:
andreev551 [17]4 years ago
8 0
In this question letter A)He saw the catcher catch the ball first,  would be true 
Juli2301 [7.4K]4 years ago
6 0

Answer: The answer is A

Explanation:

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What is a topgraphic map?
Anuta_ua [19.1K]

Answer:

A topographic map is a map that indicates the features of the land's surface, such as mountains, hills, and valleys. This is usually done with wavy lines that represent the curves and elevation of the land.

8 0
3 years ago
A machine has a mechanical advantage of 5. if 300 newtons of input force is used to produce 3,000 newton meters of work what is
Arte-miy333 [17]
F(in) x d(in)= F(out)x d(out)
A machine has a mechanical advantage of 5.
F(out )= 5xF(in)300 newtons

F(in) = 300 N
F(out)= 5xF(in) = 5x300 N
= 1500 N

Work in = Work out = 3000 N x m3000
N x m = F_in x d_ind_in = 3000 Nxm / F_in = 3000 N x m / 300 N = 10 m3000 Nxm = F_out x d_out d_out = 3000 Nx m / F_out = 3000 N x m / 1500 N = 2 m
8 0
4 years ago
To meet a U.S. Postal Service requirement, employees' footwear must have a coefficient of static friction of 0.5 or more on a sp
liq [111]

Answer:

Minimum time interval (t2)=0.90 SECONDS

Explanation:

  • coefficient of friction for employees footwear = 0.5
  • coefficient of friction for typical athletic shoe = 0.810
  • frictional force = coefficient of friction X acceleration due to gravity X mass of body
  • Acceleration due to gravity is a constant = 9.81 m/s
  • Let frictional force for employee footwear = FF1
  • Let frictional force for athletic footwear =FF2

                 FF1 = O.5 X 9.81 X mass of body

                         = 4.905 x mass of body

                  FF2 = 0.810 X 9.81 X mass of body

                          = 7.9461 x mass of body

The body started from rest there by making the initial velocity zero ( u = 0)

From d= ut + 1/2 a x t^{2}

  •      d = \frac{1}{2} x a x t^{2}  .....................................i  

            where d= distance and it is given as 3.25m

  •          F =ma  ...................................ii

making acceleration subject of the formula from equation ii

  •              a =\frac{F}{m}

         Making t subject of formula from equation (i)

  • t=\sqrt{\frac{2d}{(f/m} }

    where

  • \frac{FF1}{Mass of body} = 4.905
  • \frac{FF2}{Mass of body} =7.9461

  Let

  •            t1 = minimum time taken for frictional force for employee foot wear
  •                                 t1 = \sqrt{\frac{6.5}{4.905} } =1.15 seconds

  •                                  t2 = \sqrt{\frac{6.5}{7.9461} } = 0.90 seconds

 

THANK YOU

5 0
3 years ago
Which of the following is not an example of work??
agasfer [191]

I would say B

Because technically if your just holding it your not doing anything

-May



5 0
3 years ago
NEED HELP ASAP QUIZ PLEASE
zmey [24]
Blank 1 Thermal energy
Blank 2 heat
Thermal energy is the total energy of the particles.
Heat is the movement of thermal energy from a substance at a higher temperature to another at a lower temperature
6 0
3 years ago
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