Let's solve this by substitution.
y is given by the 2nd eqn as y = (1/3)x + 7. Subst. (1/3)x + 7 into the first eqn as a replacement for y: x + 9( (1/3)x + 7) = 3.
clear out fractions by mult. all 3 terms by 3: 3x + 9x + 63 = 3
Combine like terms: 12x = -60. Then x = -5
Find y by subst. -5 for x in the 2nd equation: y = (1/3)(-5) + 7
= -5/3 + 35/3 = 30/3 = 10.
Thus, the solution (x,y) of this system is (-5,10).
It would be 8 because 3 less than 8.
Hope this helps! :D
Answer:
(x + 3)(x - 1)(x + 2)
Step-by-step explanation:
The fractions are:
Factor each denominator
We must find the least common multiple of the denominators. We take the maximum power of each separate factor.
Factors of first fraction = (x + 3) × (x - 1)
Factors of second fraction = (x + 3) × (x + 2)
LCM = (x + 3)(x - 1)(x + 2)
The lowest common denominator of the two fractions is (x + 3)(x - 1) (x + 2).
Amount of chemical A mixed in medicine = 9.357 g
Amount of chemical B mixed in medicine = 12.082 g
Amount of chemical C mixed in medicine = 7.502 g
We have to determine the total amount of medicine he prepared in grams.
Total amount of medicine
= 9.357 + 12.082 + 7.502
= 28.941 grams
So, he prepared 28.941 grams of medicine.
Now, we have to round each chemical to the nearest tenth.
Amount of chemical A mixed in medicine = 9.357 g
Rounding to nearest tenth = 9.4 grams
Amount of chemical B mixed in medicine = 12.082 g
Rounding to nearest tenth = 12.1 grams
Amount of chemical C mixed in medicine = 7.502 g
Rounding to nearest tenth = 7.5 grams
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