N= 15
M= 15 √ 3
Brainliest please
Answer:
its the third one
Step-by-step explanation:
Answer:
Step-by-step explanation:
sin 45 = opposite / hypotenuse
<u>Where opposite = x , hypotenuse = 4</u>
sin 45 = x / 4
![\sf \frac{\sqrt{2} }{2 } = \frac{x}{4} \\\\x = \frac{4\sqrt{2} }{2} \\\\x = 2\sqrt{2} \\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20%5Cfrac%7B%5Csqrt%7B2%7D%20%7D%7B2%20%7D%20%3D%20%5Cfrac%7Bx%7D%7B4%7D%20%5C%5C%5C%5Cx%20%3D%20%5Cfrac%7B4%5Csqrt%7B2%7D%20%7D%7B2%7D%20%5C%5C%5C%5Cx%20%3D%202%5Csqrt%7B2%7D%20%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
<h3>Answer:</h3>
2/15
<h3>Explanation:</h3>
There are 8C2 = 28 ways to choose 2 dimes from the 8 dimes in Annie's purse. There are 21C2 = 210 ways to choose 2 coins from the 21 coins in Annie's purse.
Of the 210 ways to choose 2 coins, 28 of the choices will result in 2 dimes being chosen. The probability of choosing 2 dimes is 28/210 = 2/15.
_____
<em>Comment on nCk</em>
The number of ways to choose k objects from n, when order does not matter, is ...
... n!/(k!(n -k)!)
For the computations above, we have ...
... 8C2 = 8·7/(2·1) = 28
... 21C2 = 21·20/(2·1) = 210
