I hope this answer helps, it’s kinda messy, but it’s still understandable (I guess)
Answer:
the 2nd one
Step-by-step explanation:
The dimensions that would result to maximum area will be found as follows:
let the length be x, the width will be 32-x
thus the area will be given by:
P(x)=x(32-x)=32x-x²
At maximum area:
dP'(x)=0
from the expression:
P'(x)=32-2x=0
solving for x
32=2x
x=16 inches
thus the dimensions that will result in maximum are is length=16 inches and width=16 inches
the value of Y is when X crosses the X axis.
