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Finger [1]
3 years ago
7

6 numbers form an arithmetic sequence with a common difference of 4. THe sum of these numbers equals 12. What are the 6 numbers.

Mathematics
1 answer:
frutty [35]3 years ago
5 0

Answer: See explanation

Step-by-step explanation:

We will use the formula for an arithmetic sequence which will be:

a + (n - 1)d

where a = unknown

n = 6

d = 4

We then slot them into the formula

a + (6 - 1)4 = 12

a + 5(4) = 12

a + 20 = 12

a = 12 - 20

a = -8

The 6 numbers are

1st term = -8

2nd term = -8 + 4 = -4

3rd term = -4 + 4 = 0

4th term = 0 + 4 = 4

5th term = 4 + 4 = 8

6th term = 8 + 4 = 12

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Veseljchak [2.6K]
DO NOT LISTEN TO THE OTHER PERSON, you can CLEARLY see thats not the right answer. She/He is bluffing.

The true answer:
The shape has 4 faces. Faces means the sides of a 3d figure/the sides are the 2d shapes that form together to form one 3d figure. Btw that figure is a triangular pyramid.
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4 0
3 years ago
A rectangles length is 2 meters greater than its width if the e perimeter is greater than 112 what is the rectangles possible wi
pishuonlain [190]

Answer:

Step-by-step explanation:

Perimeter of a rectangle = 2(L +W)        

Given L = W + 2      and the perimeter is greater than 112 meters?

  P rect    <   2(L +W)        L = W + 2

  P rect    <   2(W + 2 +W)

                <   2(2W+2)

  112         <     4W + 4        solve for W

(112 - 4)/4  <   (4W +4 - 4)/4              

108/4       <   (4W + 0)/4

       27     <    W              

      the width has to be greater than 27 meters

   

5 0
3 years ago
Help meeeeeeeeeeeeeee ​
Travka [436]

Answer:

b. 4 min   c. 5 min

Step-by-step explanation:

6 0
2 years ago
The following table shows the number of hours some teachers in two schools expect students to spend on homework each week: Schoo
Lerok [7]

Answer:

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5

No, the box plots are not symmetric.

Step-by-step explanation:

Part A

The given data sets are

School A : 9,14,15,17,17,7,15,6,6

School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set in four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

Interquartile range of the data is

IQR=Q_3-Q_1=16-6.5=9.5

For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

Interquartile range of the data is

IQR=Q_3-Q_1=15.5-8=7.5

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data set are different.

4 0
3 years ago
Find the measure of DA
Keith_Richards [23]

Answer:

15

Step-by-step explanation:

First, find x

set your formula up as 3x+5=6x-10, since AB and DC are the same length.

This means x = 5

Now substitute 5 for x in the line DA

4x-5

4 * 5 - 5 = 15

6 0
2 years ago
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