The rate of change in temperature is −17°F/min
<h3>Rate of change of a function</h3>
The formula for calculating the rate of change of a function is expressed as:
Rate of change = rise/run
This is also known as the slope of the function
Given the following parameters
Temperature = −25.5°F
Cooling time = 1.5mins
Determine the rate of change
Rate = −25.5°F/1.5min
Rate = −17°F/min
Hence the rate of change in temperature is −17°F/min
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Answer:
1 Cups (US) = 0.24992635042 Quarts
either divide or multiply by 0.24992635042
52* 0.24992635042 = 13
13 / 0.24992635042 = 52
Step-by-step explanation:
If you are using a calculator, simply enter 16÷72×100 which will give you 22.22 as the answer.
The answer is C because it’s going back 5 times meaning it’s -5
Suppose the larger pump alone can empty the tank in L hours, and the smaller pump can finish the job in S hours, then each hour the large pump empties 1/L portion of the tank, and the small pump empties 1/S per hour
Working together for three hours, they empty the whole tank, which is 100% of it, so 3/L+3/S=100%=1
Larger pump can empty the tank in 4 hours less than the smaller one, so L=S-4
replace L: 3/(S-4)+3/S=1
Make the denominator the same to solve for:
3S/[S(S-4)] +3(S-4)/[S(S-4)]=1
(3S+3S-12)/[S(S-4)]=1
(3S+3S-12)=[S(S-4)]
S^2-10s+12=0
use the quadratic formula to solve for S
S is about 8.6
The answer is not whole hour.
