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Olegator [25]
3 years ago
12

Scientists may design an experiment with a control group, which is a set of organisms or sam-ples that do NOT receive the treatm

ent (the independent variable) that is being tested. Scientists can then compare normal changes in organisms or samples with those that might have occurred because of the treatment. The idea of a "control group" is not the same as a "controlled variable." Suppose a scientist is doing an experiment to determine the effect of a cancer drug on mice with lymphoma
Chemistry
1 answer:
Anestetic [448]3 years ago
5 0

Answer:

See explanation

Explanation:

I believe that the aim of the scientist is to determine the effect of a cancer drug on mice with lymphoma. In this experiment, the mice with lymphoma are exposed to the drug. This is the treatment in the experiment. A control group of mice having lymphoma is not exposed to this treatment, this is the control group. This control group establishes a baseline for the study.

By comparing the outcome of the experimental and control groups, the effect of a cancer drug on mice with lymphoma can be determined.

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How many kilometers can the car travel on the amount of gasoline that would fit in a soda can? The volume of a soda can is 355 m
g100num [7]
I'll assume that the car is a Honda Insight with <span>EPA gas mileage rating of 57mi/gal in the city.

First, we will convert all units into Km and mL:
1 mile = </span><span>1.609344 Km
</span><span>1gal = 3785.411 mL
</span>
Then, we will calculate the distance the car can move by multiplying the mileage rating and the the volume available as follows (note that I will be converting units in the same step):
distance = <span>(57mi/gal) x (1.609344 km/1mi) x (1gal/3785.411mL) x 355mL 
               = 8.6027 Km</span>
4 0
4 years ago
Read 2 more answers
Assume that helium behaves as an ideal monatomic gas. If 2 moles of helium undergo a temperature increase of 100 k at constant p
Helga [31]

4157 J work is done by the gas , If 2 moles of helium undergo a temperature increase of 100 K at constant pressure.

<h3>What are Noble Gases ?</h3>

The noble gases are helium, argon, krypton, xenon, and radon, in order of their mass.

They are called noble gases because they are so majestic that they do not react with anything in general.

The work done can be calculated by the formula

Q=n Cp ΔT

Cp= ( 1+ f/2)R

R= 8.3144598 J. mol-1.

Cp = (1+3/2) * 8.314

Cp = 5*8.314/2

Q= 2 * 5 *8.314 *100/2

Q = 4157 J

Therefore 4157 J work is done by the gas , If 2 moles of helium undergo a temperature increase of 100 K at constant pressure.

To know more about Noble Gas

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3 0
2 years ago
How many moles of NaCl will react completely with 18.5 L F2 gas at 300.0 K and 1.00 atm?
meriva
Hello!

Data:

P (pressure) = 1 atm
V (volume) = 18.5 L
T (temperature) = 300 K
n (number of mols) = ? (in mol)
R (Gas constant) = 0.082 (atm*L/mol*K)

Apply the data to the Clapeyron equation (ideal gas equation), see:
P*V = n*R*T

1*18.5 = n*0.082*300

18.5 = 24.6n

24.6n = 18.5

n =  \dfrac{18.5}{24.6}

\boxed{\boxed{n \approx 0,752\:mol}}\end{array}}\qquad\checkmark

Note: If the feedback is to be considered, the closest response is 0.751 mol Nacl

_________________
_________________

I hope this helps. =)


3 0
3 years ago
What will most likely happen when a warmer air mass exists above a polar ice sheet?
Andre45 [30]
I believe it is "The temperature of the ice sheet will be lowered" because it will most likely lower just a bit due to the heat. It's not going to fully melt but it will lower just a bit.
 Plus I like your profile pic.
8 0
3 years ago
Read 2 more answers
Please answer C...........
sergij07 [2.7K]

CH₃-CH(-CH₃)-CH(-CH₃)-CH₃

2,3-dimethyl-1-butane

Explanation:

We have the following chemical reaction:

CH₂=C(-CH₃)-CH(-CH₃)-CH₃ + H₂ → CH₃-CH(-CH₃)-CH(-CH₃)-CH₃

So 2,3-dimethyl-1-butene will react with hydrogen to produce 2,3-dimethyl-1-butane.

Learn more about:

hydrogenation of double bonds in organic compounds

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4 0
4 years ago
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