Answer: D
Explanation:
This is the answer because everyone knows he discovered gravity and he conducted scientific experiments to prove them which he also used math for
Hope this helps
Answer:
![P_T=112.4torr](https://tex.z-dn.net/?f=P_T%3D112.4torr)
Explanation:
Hello there!
In this case, since these problems about gas mixtures are based off Dalton's law in terms of mole fraction, partial pressure and total pressure, we can write the following for hydrogen, we are given its partial pressure:
![P_{H_2}=x_{H_2}*P_T](https://tex.z-dn.net/?f=P_%7BH_2%7D%3Dx_%7BH_2%7D%2AP_T)
And can be solved for the total pressure as follows:
![P_T=\frac{P_{H_2}}{x_{H_2}}](https://tex.z-dn.net/?f=P_T%3D%5Cfrac%7BP_%7BH_2%7D%7D%7Bx_%7BH_2%7D%7D)
However, we first calculate the mole fraction of hydrogen by subtracting that of nitrogen to 1 due to:
![x_{H_2}+x_{N_2}=1\\\\x_{H_2}=1-0.333=0.667](https://tex.z-dn.net/?f=x_%7BH_2%7D%2Bx_%7BN_2%7D%3D1%5C%5C%5C%5Cx_%7BH_2%7D%3D1-0.333%3D0.667)
Then, we can plug in to obtain the total pressure:
![P_T=\frac{75.0torr}{0.667}\\\\P_T=112.4torr](https://tex.z-dn.net/?f=P_T%3D%5Cfrac%7B75.0torr%7D%7B0.667%7D%5C%5C%5C%5CP_T%3D112.4torr)
Regards!
<u>Answer:</u> The
for the reaction is 72 kJ.
<u>Explanation:</u>
Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.
According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.
The given chemical reaction follows:
![\Delta H^o_{rxn}=?](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%3F)
The intermediate balanced chemical reaction are:
(1)
![\Delta H_1=-1184kJ](https://tex.z-dn.net/?f=%5CDelta%20H_1%3D-1184kJ)
(2)
( × 2)
(3)
( × 2)
The expression for enthalpy of the reaction follows:
![\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[2\times (-\Delta H_2)]+[2\times (\Delta H_3)]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B1%5Ctimes%20%28%5CDelta%20H_1%29%5D%2B%5B2%5Ctimes%20%28-%5CDelta%20H_2%29%5D%2B%5B2%5Ctimes%20%28%5CDelta%20H_3%29%5D)
Putting values in above equation, we get:
![\Delta H^o_{rxn}=[(1\times (-1184))+(2\times -(-234))+(2\times (394))]=72kJ](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%281%5Ctimes%20%28-1184%29%29%2B%282%5Ctimes%20-%28-234%29%29%2B%282%5Ctimes%20%28394%29%29%5D%3D72kJ)
Hence, the
for the reaction is 72 kJ.
Yes it is ========== covalent bond