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3 years ago

Explain why BH3 is trigonal planar and NH3 is trigonal pyramidal.

1 answer:

3 0

Answer:o It is important to realise that mixing will be small unless there are electrons in the 4a1 LUMO, this is why NH3 is pyramidal while BH3 is planar! ... This mixing is very strong and stabilises the 3a1 MO substantially and hence NH3 is trigonal pyramidal and not planar.

Explanation:

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How many grams of tin would occupy 5.5 L if it had a density of 7.265

lisabon 2012 [21]

In order to find the mass of tin with the given volume of 5.5 L and density of 7.265, we will use the formula
Density = Mass / Volume

We will just multiply both sides of the equation by the volume and we will get:
Mass = Volume x Density

We can now solve the problem by substituting the given.

Mass = 5.5 L x 7.265 g/L
Mass = 39.96 g

Answer: there are 39.96 grams of tin

7 0

3 years ago

How many solutions are there to the graph below

GuDViN [60]

Answer:

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8 0

3 years ago

How many coulombs are required to plate a layer of chromium metal 0.28 mm thick on an auto bumper with a total area of 0.40 m2 f

Rufina [12.5K]

Explanation:

The given data is as follows.

Thickness = 0.28 mm = $0.28 \times \frac{1}{10}$ cm = 0.028 cm

Area = 0.40 $m^{2}$ = $0.40 \times 10^{4} cm^{2}$ = 4000 $cm^{2}$

As, it is known that volume = area × thickness

So, Volume = $4000 cm^{2} \times 0.028 cm$

= 112 $cm^{3}$

As density is mass divided by volume. So, mass of chromium will be calculated as follows.

Density = $\frac{mass}{volume}$

7.20 $g/cm^{3}$ = $\frac{mass}{112 cm^{3}}$

mass = 806.4 g

As, mass of 1 mole of chromium is 52 g. So, number of moles in 806.4 g of chromium will be as follows.

No. of moles = $\frac{mass}{molar mass}$

= $\frac{806.4 g}{52 g}$

= 15.50 mol

In chromate ion, ( $CrO^{2-}_{4}$ ) charge on Cr is +6. It means that 6 electrons are needed to reduce $Cr^{+6}$ into Cr.

As, 1 mole of $Cr^{+6}$ ions require 6 moles of electrons. Therefore, moles of electrons for 15.50 mol will be calculated as follows.

6 × 15.50 mol = 93.04 mol

To calculate number of electrons we multiply number of moles by Avogadro's number as follows.

$93.04 mol \times 6.02 \times 10^{23}$

= $560.13 \times 10^{23}$

= $5.6 \times 10^{25}$ electrons

There is magnitude of $6.241 \times 10^{18}$ times the charge on an electron is equal to 1 coulomb.

Hence, number of coulombs will be as follows.

No. of coulombs = $\frac{5.6 \times 10^{25}}{6.241 \times 10^{18}}$

= $0.897 \times 10^{7}$ C

or, = $8.97 \times 10^{6}$ C

Thus, we can conclude that $8.97 \times 10^{6}$ C are required to plate a layer of chromium metal with given data.

4 0

3 years ago

A film crew is setting up a scene to show the effects of a blast wave on nearby cars. Why do you think the cars are hanging from

PSYCHO15rus [73]

The cars are hanging from cables so that there is presence of more medium of propagation to make it look real.

<h3>What is a Blast wave?</h3>

This is referred to as a violent propagating disturbance, produced by an explosion in air.

Hanging the cars in the air will ensure an accurate description of the effect of the blast wave on them.

Read more about Blast wave here brainly.com/question/13446916

3 0

2 years ago

How can increase the rate of the preparation copper i iodide?

BARSIC [14]

Answer:

Preparation. Copper(I) iodide can be prepared by heating iodine and copper in concentrated hydriodic acid, HI. In the laboratory however, copper(I) iodide is prepared by simply mixing an aqueous solution of potassium iodide and a soluble copper(II) salt such copper sulfate.

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3 years ago