(X-1) squared + y squared = 36. What is the center and radius of the circle
1 answer:
Answer:
- center (1, 0)
- radius 6
Step-by-step explanation:
<u>Given</u>
(x -1)^2 +y^2 = 36
<u>Find</u>
the circle's center and radius
<u>Solution</u>
Compare the given equation to the standard form equation for a circle.
(x -h)^2 +(y -k)^2 = r^2 . . . . . . centered at (h, k) with radius r
This tells you ...
- h = 1
- k = 0
- r = √36 = 6
Your circle is centered at (1, 0) and has a radius of 6.
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Answer:
Step-by-step explanation:
Slope-intercept form: y = mx + b
Slope formula:
Given points: (3, -7), (7, 2)
(3, -7) = (x1, y1)
(7, 2) = (x2, y2)
To write the equation in slope-intercept form, we need to find the slope(m) and the y-intercept(b) of the equation.
First, let's find the slope. To do this, input the given points into the slope formula:
Simplify:
2 - (-7) = 2 + 7 = 9
7 - 3 = 4
The slope is .
To find the y-intercept, input the slope and one of the given points(in this example I'll use point (7, 2)) into the equation and solve for b:
The y-intercept is .
Now that we know the slope and the y-intercept, we can write the equation: