Joshua delivered 30 hives to the local fruit farm.
If the farmer has paid to use 5% of the total number of Joshua's hives.
So 30 hives is 5% of the total number of hives.
5% of hives = 30
1% of hives = 30 ÷ 5 = 6
100% of hives = 6 × 100 = 600
Thus, Joshua had 600 hives before selling.
Now, he has = 600 - 30 = 570 hives.
Now, Joshua has 570 hives.
Answer:
Step-by-step explanation:
we know that
The standard equation of a horizontal parabola is equal to
where
(h,k) is the vertex
(h+p,k) is the focus
In this problem we have
(h,k)=(0,0) ----> vertex at origin
(h+p,k)=(-4,0)
so
h+p=-4
p=-4
substitute the values
Answer:
Subtract 5x from both sides of the equation.
7y=1−5x
x+4y=−5
Divide each term by 7 and simplify.
y=17−5x/7
x+4y=−5
Subtract x from both sides of the equation.
y=1/7−5x/7
4y=−5−x
y=1/7−5x/7
Divide each term by 4 and simplify.
y=1/7−5x/7
y=−5/4−x/4
y=1/7−5x/7
Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution. (3,−2)
Step-by-step explanation:
The percentage of young adults send between 128 and 158 text messages per day is; 34%
<h3>How to find the percentage from z-score?</h3>
The distribution is approximately Normal, with a mean of 128 messages and a standard deviation of 30 messages.
We are given;
Sample mean; x' = 158
Population mean; μ = 128
standard deviation; σ = 30
We want to find the area under the curve from x = 248 to x = 158.
where x is the number of text messages sent per day.
To find P(158 < x < 248), we will convert the score x = 158 to its corresponding z score as;
z = (x - μ)/σ
z = (158 - 128)/30
z = 30/30
z = 1
This tells us that the score x = 158 is exactly one standard deviation above the mean μ = 128.
From online p-value from z-score calculator, we have;
P-value = 0.34134 = 34%
Approximately 34% of the the population sends between 128 and 158 text messages per day.
Read more about p-value from z-score at; brainly.com/question/25638875
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Answer:
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Step-by-step explanation:
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