All categories

3 years ago

(-3,-14) and (0-9) Pls help!!!

Mathematics

1 answer:

andreyandreev [35.5K]3 years ago

3 0

Answer:

y = (5/3)x - 9

Step-by-step explanation:

First, find the slope (rise over run):

m = (-9 - (-14)) / (0 - (-3)) = (-9 + 14) / (0 + 3) = 5/3

Use the point-slope form equation with the given points (-3, -14):

y + 14 = (5/3)(x + 3)

or optionally in slope intercept form:

y = (5/3)x - 9

You might be interested in

Help please, I’m not sure

umka21 [38]

YOUR ANSWER IS A
HOPE THIS HELPS

5 0

3 years ago

Write 0.31% as a decimal.

Varvara68 [4.7K]

Answer:

0.31% = 0.0031 in decimal form.

Step-by-step explanation:

Percent means 'per 100'. So, 0.31% means 0.31 per 100 or simply 0.31/100. If you divide 0.31 by 100, you'll get 0.0031 (a decimal number).

8 0

3 years ago

A player of a video game is confronted with a series of opponents and has an 80% probability of defeating each one. Success with

Vikentia [17]

Answer:

(a) The PMF of X is: $P(X=k)=(1-0.20)^{k-1}0.20;\ k=0, 1, 2, 3....$

(b) The probability that a player defeats at least two opponents in a game is 0.64.

(d) The probability that a player contests four or more opponents in a game is 0.512.

(e) The expected number of game plays until a player contests four or more opponents is 2.

Step-by-step explanation:

Let X = number of games played.

It is provided that the player continues to contest opponents until defeated.

(a)

The random variable X follows a Geometric distribution.

The probability mass function of X is:

$P(X=k)=(1-p)^{k-1}p;\ p>0, k=0, 1, 2, 3....$

It is provided that the player has a probability of 0.80 to defeat each opponent. This implies that there is 0.20 probability that the player will be defeated by each opponent.

Then the PMF of X is:

$P(X=k)=(1-0.20)^{k-1}0.20;\ k=0, 1, 2, 3....$

(b)

Compute the probability that a player defeats at least two opponents in a game as follows:

P (X ≥ 2) = 1 - P (X ≤ 2)

= 1 - P (X = 1) - P (X = 2)

$=1-(1-0.20)^{1-1}0.20-(1-0.20)^{2-1}0.20\\=1-0.20-0.16\\=0.64$

Thus, the probability that a player defeats at least two opponents in a game is 0.64.

(c)

The expected value of a Geometric distribution is given by,

$E(X)=\frac{1}{p}$

Compute the expected number of opponents contested in a game as follows:

$E(X)=\frac{1}{p}=\frac{1}{0.20}=5$

Thus, the expected number of opponents contested in a game is 5.

(d)

Compute the probability that a player contests four or more opponents in a game as follows:

P (X ≥ 4) = 1 - P (X ≤ 3)

= 1 - P (X = 1) - P (X = 2) - P (X = 3)

$=1-(1-0.20)^{1-1}0.20-(1-0.20)^{2-1}0.20-(1-0.20)^{3-1}0.20\\=1-0.20-0.16-0.128\\=0.512$

Thus, the probability that a player contests four or more opponents in a game is 0.512.

(e)

Compute the expected number of game plays until a player contests four or more opponents as follows:

$E(X\geq 4)=\frac{1}{P(X\geq 4)}=\frac{1}{0.512}=1.953125\approx 2$

Thus, the expected number of game plays until a player contests four or more opponents is 2.

4 0

3 years ago

Rodger is riding in a bike-a-thon to raise money for his favorite charity. The total distance of the bike of stone is 38.7 miles

Len [333]

Did u mean miles? cause it says "mouse"

8 0

4 years ago

Read 2 more answers

Jade used Fraction 3 over 4 yard of fabric to make a scarf. Can she make 2 of these scarves with Fraction 1 and 4 over 5 yards o

DochEvi [55]

Used 3/4 to make scarf

2 scarves needs 3/4+3/4=6/4=3/2 yard

can it be made with 1 and 4/5?
1 and 4/5=5/5+4/5=9/5
compare 3/2 and 9/5
times first fraction by 5/5 and 2nd by 2/2
15/10 and 18/10
15/10<18/10
yes, has enough
confused by the division, please use parenthasees like (3/4) instead of 'fraction 3 over 4'

C or D, very confused by words that are many

8 0

4 years ago

Read 2 more answers