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3 years ago

In the problem solving process, the final step is to try to ______.

2 answers:

5 0

The final steps is to review your results.

This means that you have to check if the results meet the original requirements or statements.

Ideally, you should try to solve the same problem by a second method, and/or you should substitute the results into the given relationships given in the problem statement to chek coherence of your results.

Then the answer is option b.

Phantasy [73]3 years ago

3 0

B. review your results

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Find the gcf of each pair of number 24 and 56

pshichka [43]

8is the correct answer

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3 years ago

1 Which expression is equivalent to (7x – 5) – (3x - 2)?

Mila [183]

Answer:

The answer is D.

Step-by-step explanation:

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3 years ago

Can someone help me? Solve for x.

Luda [366]

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3 years ago

Loretta’s income last year was $81,300. She made $56,800 at her salaried job and had additional passive income. If Loretta earne

aalyn [17]

Answer:

Option a. $2,040

Step-by-step explanation:

step 1

To find out the amount of the additional passive income last year, subtract the amount earned at her salaried job from Loretta’s income last year

$\$81,300-\$56,800=\$24,500$

step 2

Divide the additional passive income last year by 12 (number of months in a year)

$\$24,500/12=\$2,041.67$

therefore

approximately $2,400 per month

5 0

3 years ago

Read 2 more answers

HELPP!!!!!!!!!!!!!!!!

Anvisha [2.4K]

Answer:

Step-by-step explanation:

We'll take this step by step. The equation is

$8-3\sqrt[5]{x^3}=-7$

Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time. First thing is to subtract 8 from both sides:

$-3\sqrt[5]{x^3}=-15$

The goal is to isolate the term with the x in it, so that means that the -3 has to go. Divide it away on both sides:

$\sqrt[5]{x^3}=5$

Let's rewrite that radical into exponential form:

$x^{\frac{3}{5}}=5$

If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:

$(x^{\frac{3}{5}})^{\frac{5}{3}}=5^{\frac{5}{3}}$

On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely. On the right, let's rewrite that back in radical form to solve it easier:

$x=\sqrt[3]{5^5}$

Let's group that radicad into groups of 3's now to make the simplifying easier:

$x=\sqrt[3]{5^3*5^2}$ because the cubed root of 5 cubed is just 5, so we can pull it out, leaving us with:

$x=5\sqrt[3]{5^2}$ which is the same as:

$x=5\sqrt[3]{25}$

8 0

3 years ago